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igor_vitrenko [27]
3 years ago
9

Pls help asap, ill give brainiest

Mathematics
1 answer:
zloy xaker [14]3 years ago
8 0

The answer is D

If this helped a brainliest would be appreciated!

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Write two equivalent fractions for 5/10
shtirl [24]
1/2 and 10/20

to get 1/2 you have to divide 5/10 by 5:

  5   /   5          1     
-----          =   ----- 
 10  /   5          2

to get 10/20 you have to multiply 5/10 by 2:

  5   *   2          10
-----           =    ----
 10  *   2          20

Hope it helps! =)
7 0
3 years ago
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What is the value of the expression when n=3 -2(5+n-8-3n)
Greeley [361]
-2n(5 + n - 8 - 3n)
-10n - 2n² + 16n + 6n²
4n² + 6n
7 0
3 years ago
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Which is the correct pairs?
jarptica [38.1K]

Answer:

5 and 6 are examples of vertical angles.

Step-by-step explanation:

Vertical angles are two angles on opposite sides of an intersection of two lines. This is exactly what we see in this picture with 5 and 6

7 0
3 years ago
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36/45 reduced in the lowest terms
malfutka [58]

Answer:

\frac{4}{5}

Step-by-step explanation:

They both (36 and 45) go into 9. Divide them both by 9.

\frac{4}5}

6 0
4 years ago
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Six​ stand-up comics,​ A, B,​ C, D,​ E, and​ F, are to perform on a single evening at a comedy club. The order of performance is
kiruha [24]

Answer:

a) 1/6

b) 1/36

c) 1/720

d) 1/3

Step-by-step explanation:

a) Any of the six comics can perform in the fourth place, so there is one chance in six that Comic F is the one that performs fourth.

P(F=4th)=1/6

b) In this case, we have two conditions. Both are independent of each other, so the probability of both happening is the product of the probabilities of each happening individually:

P(D=4th \&B=2nd)=P(D=4th)\cdot P(B=2nd)=(1/6)\cdot(1/6)=1/36

c) This combination is one in all possible orders of perform. The amount of combinations of orders is n!=6!=720 possible combinations. So the probability of this specific order is:

P(F, D, B, A, C, E)=1/720

d) In this case, of the six possible comics performing in the last place, we calculate the probability of 2 of them being in that place. So the probability is:

P(C=6th\,or\, E=6th)=2/6=1/3

8 0
3 years ago
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