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Alenkasestr [34]
3 years ago
12

HALP MEEEEEEE!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Lesechka [4]3 years ago
8 0

Answer: 4

Step-by-step explanation:

Naddika [18.5K]3 years ago
5 0
Answer is 4 btw good luck on the assignment
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K(n) = 4n+5<br><br> Find k(-3n)
vitfil [10]
Plug in -3n as n into the functon K(n)=4n+5
so you get
K(-3n)=4(-3n)+5
K(-3n)=-12n+5
7 0
4 years ago
What is the difference between online school and in-person
geniusboy [140]

Answer:

The difference between online school and in person school is that online is online and inperson is in person.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Two cars are on the same straight road. Car A moves east at 55 mph and sounds its horn at 625 Hz. Rank from highest to lowest th
Fantom [35]

Answer:

1. Car B is moving east at 70MPh and is in from of car A

2.car B is moving west at 70 mph and is behind car A

Step-by-step explanation:

Use the cardinal point system to evaluate the problem first

8 0
3 years ago
Help on math? Thanks
Anuta_ua [19.1K]
C is the answer

Dmmssmsmsmxmxxmxm
5 0
3 years ago
supervisor records the repair cost for 25 randomly selected dryers. A sample mean of $93.36 and standard deviation of $19.95 are
Simora [160]
<h2><u>Answer with explanation:</u></h2>

The confidence interval for population mean (when population standard deviation is unknown) is given by :-

\overline{x}-t^*\dfrac{s}{\sqrt{n}}< \mu

, where n= sample size

\overline{x} = Sample mean

s= sample size

t* = Critical value.

Given : n= 25

Degree of freedom : df=n-1=24

\overline{x}= \$93.36

s=\ $19.95

Significance level for 98% confidence interval : \alpha=1-0.98=0.02

Using t-distribution table ,

Two-tailed critical value for 98% confidence interval :

t^*=t_{\alpha/2,\ df}=t_{0.01,\ 24}=2.4922

⇒ The critical value that should be used in constructing the confidence interval = 2.4922

Then, the 95% confidence interval would be :-

93.36-(2.4922)\dfrac{19.95}{\sqrt{25}}< \mu

=93.36-9.943878< \mu

=93.36-9.943878< \mu

=83.416122< \mu

Hence, the 98% confidence interval for the mean repair cost for the dryers. = 83.4161

4 0
3 years ago
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