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Alenkasestr [34]
3 years ago
12

HALP MEEEEEEE!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Lesechka [4]3 years ago
8 0

Answer: 4

Step-by-step explanation:

Naddika [18.5K]3 years ago
5 0
Answer is 4 btw good luck on the assignment
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The school that Joe goes to is selling tickets to a choral performance. On血e first day of ticket
ArbitrLikvidat [17]

Answer:

The price of one senior citizen ticket is $8, and the price of one child ticket is $11.

Step-by-step explanation:

You are looking for two things: the price of a senior citizen ticket and the price of a child ticket.

We need to write two equations using two variables.

Let s = price of 1 senior citizen ticket.

Let c = price of 1 child ticket.

First day of ticket sales:

6 senior citizen tickets, 8 child tickets, total sales of $136

Since s is the price of a senior citizen ticket, 6 tickets cost 6s.

Since c is the price of a child ticket, 8 tickets cost 8c.

The total sales is 6s + 8c.

The total sales is $136, so our first equation is

6s + 8c = 136

Now we do the same for the second day of ticket sales.

6 senior citizen tickets, 9 child tickets, total sales of $147.

Since s is the price of a senior citizen ticket, 6 tickets cost 6s.

Since c is the price of a child ticket, 9 tickets cost 9c.

The total sales is 6s + 9c.

The total sales is $147, so our second equation is

6s + 9c = 147

The system of equations is

6s + 8c = 136

6s + 9c = 147

Multiply both sides of the first equation by -1. Write the second equation below it. Then add the equations.

       -6s - 8c = -136

(+)     6s + 9c = 147

----------------------------

                  c =   11

c = 11, so the cost of a child ticket is $11.

Now substitute 11 for c in the first equation, and solve for s.

6s + 8c = 136

6s + 8(11) = 136

6s + 88 = 136

6s = 48

s = 8

The price of a senior citizen ticket is $8.

The price of a senior citizen ticket is $8, and the price of a child ticket is $11.

6 0
3 years ago
Please help me with matching formulas!!!
bonufazy [111]
1 to simple interest
2 to distance
3 to rate of interest
4 to time money is invested
5 to time spent driving
6 to rate of speed
8 0
3 years ago
A cone is 10 inches tall and has a radius of 3 inches. What is the cone's volume?
Mandarinka [93]
The Answer is 94.2 cubic inches
7 0
3 years ago
Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)
Leni [432]
Alrighty

remember some rules
(ab)^c=(a^c)(b^c)
and
x^{-m}=\frac{1}{x^m}
and
x^0=1 for all real values of x
and
(a^b)^c=a^{bc}
and
(\frac{a}{b})^c=\frac{a^c}{b^c}
and
(a/b)/(c/d)=(ad)/(bc)
and
(a^b)(a^c)=a^{b+c}
and
\frac{a^m}{a^n}=a^{m-n}
and don't forget pemdas
example: -x^m=-1(x^m) but (-x)^m=(-1)^m(x^m)

so

4.
(\frac{c^{-2}}{2})^{-2}=

\frac{(c^{-2})^{-2}}{2^{-2}}=

\frac{c^4}{\frac{1}{2^2}}=

\frac{c^4}{\frac{1}{4}}=

4c^4



5.

\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=

\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=

\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=

\frac{(a^4bc^5)b^3}{(-1)(a^2)}=

\frac{-a^4b^4c^5}{a^2}=

-a^2b^4c^5
3 0
3 years ago
One large box of birdseed can feed half a dozen parrots for 15 days. For how many days can this same large box of birdseed feed
iren [92.7K]
Box = b
Parrots = p
b/p = number of days it can support the parrots
Half a dozen = 6 (A dozen is 12)
1/6 = 15
To work out the percentage of '6' '5' is, use the equation
(5/6)*100 = 83.333....
Meaning that with one less bird, the box will support the birds for 16.666... (100 - 18.333...) longer
(15/100)*116.666... = 17.4999....
The box will sustain the parrots for 17.5 days
7 0
3 years ago
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