Since bc = 6, that makes db = 3 and cd = 3rad3
cd (2) = ac. so ac = 6rad3
so to get ad, you square ac which = 108, square cd which = 3rad3 which equals 27. 108 - 27 = 81. the sqaure root of 81 is 9. ad = 9
Answer:
x = - 3 ± 
Step-by-step explanation:
x² + 6x + 7 = 0 ( subtract 7 from both sides )
x² + 6x = - 7
using the method of completing the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(3)x + 9 = - 7 + 9
(x + 3)² = 2 ( take square root of both sides )
x + 3 = ±
( subtract 3 from both sides )
x = - 3 ± 
Where are the following options?