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SIZIF [17.4K]
3 years ago
15

How do I solve this equation and check all the solutions?

Mathematics
2 answers:
MrRa [10]3 years ago
8 0

Step-by-step explanation:

just hints available i cannot do more thanthat

Naily [24]3 years ago
5 0

Answer:

<em>x = 12</em>

Step-by-step explanation:

\sqrt{3x} + 10 = x + 4

\sqrt{3x} = x - 6

( \sqrt{3x} )² = ( x - 6 )²

3x = x² - 12x + 36

x² - 15x + 36 = 0

(x - 3)(x - 12) = 0

x_{1} = 3

x_{2}<em> = 12 </em>

Check the answer:

\sqrt{3*3} + 10 ≠ 3 + 4

13 ≠ 7 ⇒ 3 is not the root of original equation (strange root)

\sqrt{3*12} + 10 = 12 + 4

16 = 16 ⇒ 12 is the root of original equation

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