That person;s body weight will be 156 Ib. Do 9 3/4 times 1/16 to get you body weight
The answer to this question is C
Answer:
16 rides
Step-by-step explanation:
Option 1 . Admission fee = $10
Each ride = $0.50
Option 2 . Admission fee = $6
Each ride = $0.75
Let no. of rides be x
So, cost of ride according to option 1 = 0.50x
So, total cost after having x rides according to option 1 :
= 10+0.50x ---1
Cost of ride according to option 2 = 0.75x
So, total cost after having x rides according to option 2 :
= 6+0.75x --2
Now to find the beak even point i.e. having the same cost
Equate 1 and 2
Thus for 16 rides , the two options have the same cost .
Hence the break even point is 16 rides
<span>1. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.
What is the theoretical probability that the family has two dogs or two cats?
25% chance
</span><span>2. Describe how to use two coins to simulate which two pets the family has.
</span>
You could use the coins to simulate which pet the family has by flipping them and having head be dog and tails be cat (or vice-versa).
<span>3. Flip both coins 50 times and record your data in a table like the one below.
</span><span>Based on your data, what is the experimental probability that the family has two dogs or two cats?
</span>
Based on the results, I concluded that for Heads, Heads (which could be dogs or cats) there was a 24% chance and for Tails, Tails there was a 26% chance
<span>4. If the family has three pets, what is the theoretical probability that they have three dogs or three cats?
1/8 chance (accidentally messed up there) or 12.5%
</span><span>5. How could you change the simulation to generate data for three pets?
</span><span>
To flip 3 coins and add more spots on the chart.
I hope that this helps because it took a while to write out. If it does, please rate as Brainliest
</span>
Answer:
As below.
Step-by-step explanation:
The -4 shifts the graph to the right not the left.
The second error is the refection is over the x-axis not the y-axis.
