Answer:
8 seconds
Step-by-step explanation:
Given
h = - 5t² + 40t
When the object hits the ground then h = 0
Substitute h = 0 into the function and solve for t
- 5t² + 40t = 0 ← factor out - 5t from each term
- 5t(t - 8) = 0
Equate each factor to zero and solve for t
- 5t = 0 ⇒ t = 0
t - 8 = 0 ⇒ t = 8
t= 0 denotes the time of launch
t = 8 denotes the time it hits the ground
Answer:
The object will hit the ground after 10.308 seconds.
Step-by-step explanation:
h(t) = -16t² + 1700
If you graphed this function, the object would be shown hitting the ground when it crosses the x-axis, in other words, when h = 0. So, to find the answer, just set h(t) equal to 0 and solve.
-16t² + 1700 = 0 Plug this into a calculator if you have one.
t = -10.308 and t = 10.308
Since time can't be negative, your answer will be the positive value, 10.308.
Step-by-step explanation:
17+7x=x+5
6x=-12
x=-2
Hope it helps you
5 and 6 are true but 7 is not true. If you divide an odd number by 2 it's not going to be half of it
Answer:
x=-4 and y=0
Step-by-step explanation:
