( f + g ) (x) = –2x + 6
( f – g ) (x) = 8x – 2
( f × g ) (x) = –15x2 + 2x + 8
<span>\mathbf{\color{purple}{ \left(\small{\dfrac{\mathit{f}}{\mathit{g}}}\right)(\mathit{x}) = \small{\dfrac{3\mathit{x} + 2}{4 - 5\mathit{x}}} }}<span><span>(<span><span>g</span><span>f</span><span></span></span>)</span>(x)=<span><span><span>4−5x</span></span><span><span>3x+2</span></span><span></span></span></span></span>
If the original number is ab it has a value of
10a+b when it is reversed it will have a value of 10b-a
10b+a-10a-b is the differences which is equal to
9b-9a
So the numbers must be divisible by 9
B. -4-1. -4-1=-5, which is the amount of you count the spaces in between.
Hope this helps!
This can solved graphically, using algebraic manipulation or differential calculus.
Plotting the equation will generate a parabola. The vertex represents the point where the ball will reach the maximum height.
The vertex can be determined by completing the square
h = -16t2 + 45t + 5
h - 5 = -16(t2 - 45/16t)
h - 5 - 2025/64 = -16(t2 - 45/16t + 2025/1024)
(-1/16)(h - 2345/64) = (t - 45/32)^2
The vertex is
(45/32,2345/64) or (1.41,36.64)
The maximum height is 36.64 ft
Using calculus, taking the first derivative of the equation and equating to 0
dh/dt = 0 = -32t + 45
t = 45/32
Substituting this value to the equation
h = -16(45/32)^2 + 45(45/32) + 5
h = 36.64 ft
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The answer for the exercise shown above is the last option (Option D), which is:
D. log base 5 of 56
The explanation is show below:
1. You have the following logarithm expresssion:
<span>log5(4*7 )+log5(2)
</span>
2. By the logarithms properties, you can rewrite the logarithm expression as following:
log5(28)(2)
log5(56)
3. Therefore, as you can see, the answer is the option mention before.
