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3 years ago

Find the following (Show your work) 1) 20% of 5 2) 35% of 50 2) 71% of 22

Mathematics

1 answer:

seropon [69]3 years ago

8 0

Answer:

Step-by-step explanation:

1. 1

2. 17.5

3. 15.62

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jeyben [28]

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3 years ago

How to write the decimal for 762-222-2945

aalyn [17]

Tht is equal to -2405

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3 years ago

Geometry Special Quadrilaterals show work please

Charra [1.4K]

Answer:

a = 16

w = 125

x = 120

y = 55

Step-by-step explanation:

FINDING 'a'

31 = a + 46 / 2

62 = a + 46

16 = a

FINDING 'w'

* This section looks Non-Isosceles trapezoid so I will be following the rule according it

w + 55 = 180

w = 125

FINDING 'y'

y = 55

- Because of corresponding angles

FINDING 'x'

* In this case it looks like we are still dealing w/ an non-isosceles trapezoid.

x + 60 = 180

x = 120

Hope this helped ^^

(Please inform me of any mistakes or misunderstandings!)

6 0

3 years ago

To edit a manuscript, Miguel charges 12 dollars per hour for the first 4 hours and 15 dollars per hour after the first 4 hours.

aleksley [76]

Answer:

C = 12 + 15(x - 4)

C = 15x - 48

Step-by-step explanation:

Let the number of hours = t

The total amount Miguel earns =

To edit a manuscript, Miguel charges 12 dollars per hour for the first 4 hours and 15 dollars per hour after the first 4 hours.

C = 12 + 15(x - 4)

Expand the t

C = 12 + 15x - 60

C = 15x - 48

Therefore, an expression for the amount, in dollars, Miguel charges if it takes him t hours to edit a manuscript, where t>4 is given as:

C = 15x - 48

5 0

3 years ago

A jumbo crayon is composed of a cylinder with a conical tip. The cylinder is 12 cm tall with a radius of 1.5 cm, and the cone ha

s2008m [1.1K]

Answer:

Part 1) The lateral area of the cone is $LA=2\pi\ cm^{2}$

Part 2) The lateral surface area of the cylinder is $LA=36\pi\ cm^{2}$

Part 3) The surface area of the crayon is $SA=41.50\pi\ cm^{2}$

Step-by-step explanation:

Part 1) Find the lateral area of the cone

The lateral area of the cone is equal to

$LA=\pi rl$

we have

$r=1\ cm$

$l=2\ cm$

substitute

$LA=\pi (1)(2)$

$LA=2\pi\ cm^{2}$

Part 2) Find the lateral surface area of the cylinder

The lateral area of the cylinder is equal to

$LA=2\pi rh$

we have

$r=1.5\ cm$

$h=12\ cm$

substitute

$LA=2\pi (1.5)(12)$

$LA=36\pi\ cm^{2}$

Part 3) Find the surface area of the crayon

The surface area of the crayon is equal to the lateral area of the cone, plus the lateral area of the cylinder, plus the top area of the cylinder plus the bottom base of the crayon

Find the area of the bottom base of the crayon

$A=\pi[r2^{2}-r1^{2}]$

where

r2 is the radius of the cylinder

r1 is the radius of the cone

substitute

$A=\pi[1.5^{2}-1^{2}]$

$A=1.25\pi\ cm^{2}$

Find the area of the top base of the cylinder

$A=\pi(1.5)^{2}=2.25\pi\ cm^{2}$

Find the surface area

$SA=2\pi+36\pi+2.25\pi+1.25\pi=41.50\pi\ cm^{2}$

8 0

3 years ago

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