Rearrange the first equation
2x + y = 20
take away 2x from both sides
y = 20 - 2x
substitute this y value into the second equation
6x - 5(20 - 2x) = 12
6x -100 +10x = 12
add 100 to both sides
6x + 10x = 112
16x = 112
divide both sides by 16
x = 7
Substitute this x value into the first equation to get y.
2(7) + y = 20
14 + y = 20
take away 14 from both sides
y = 6
So, y = 6 and x = 7
The value of x from the given circle is 4
<h3>What is intersecting chord theorem?</h3>
The intersecting chords theorem is a statement in geometry that describes a relation of the four line segments created by two intersecting chords within a circle.
It states that the products of the lengths of the line segments on each chord are equal.
According to the theorem;
x * 3 = 2 * (4 + 2)
3x = 2(6)
3x = 12
Divide both sides by 3
3x/3 = 12/3
x =4
Hence the value of x from the given circle is 4
Learn more on intersecting chord theorem here; brainly.com/question/13950364
#SPJ1
<span>Why is it important to choose a bank that is a member of the FDIC?
</span><span>The FDIC is a government bureau that insures the money that customers deposit in the bank, so your money is safer in an FDIC bank.
Hope This Helped! :3</span>
I’m assuming ‘dives further’ means to go directly down
the angle of elevation of the ship from the submarine is equal to the angle of depression of the submarine from the ship, if we assume the sea level is perpendicular to ‘directly down’.
let both of these angles to be = $ when the submarine is at A and ¥ when the submarine is at B (excuse the lack of easily accessible variables as keys)
then this become a simple trig problem:
A)
Let O be the position of of the ship, and C be the original position of the submarine.
therefore, not considering direction
|OC| = 1.78km = 1780m
|CA| = 45m
these are the adjacent and opposite sides of a right angled triangle.
But tan($) = opp/adj = |CA|/|OC| = 45/1780
therefore $ = arctan(45/1780) which is roughly 1.45 degrees,
B)
similarly, noting that |CB| = |CA| + |AB| = 45 + 62 = 107m
tan(¥) = 107/1780
¥ = arctan(107/1780) which is roughly 3.44 degrees
