What is the length of the apothem, rounded to the nearest tenth?
2 answers:
See the attached figure to better understand the problem
we know that
in the triangle ABC
<span>applying the Pythagorean theorem
AC</span>²=AB²+BC²
<span>AC=8 cm
AB=apothem
BC=9.4/2-----> 4.7 cm
AB</span>²=AC²-BC²-----> 8²-4.7²-----> 64-22.09------> AB²=41.91
AB=√41.91-------> 6.47 cm---------> 6.5 cm
apothem=6.5 cm
the answer is
6.5 cm
we know that
in the triangle ABC
<span>applying the Pythagorean theorem
AC</span>²=AB²+BC²
<span>AC=8 cm
AB=apothem
BC=9.4/2-----> 4.7 cm
AB</span>²=AC²-BC²-----> 8²-4.7²-----> 64-22.09------> AB²=41.91
AB=√41.91-------> 6.47 cm---------> 6.5 cm
apothem=6.5 cm
the answer is
6.5 cm
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Answer:
x=8
NR=5 units
BI=10 units
Step-by-step explanation:
In a rectangle BRIA
AN=5 units
NR=x-3
We have to solve for x , NR and BI.
We know that
Diagonals of rectangle bisect to each other.
BI and AR are the diagonals of rectangle BRIA and intersect at point N.
AN=NR
Substitute the value of x
NR=8-3=5
By property of rectangle
BI=AR=AN+NR=5+5=10 unit
BI=10 units
