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k0ka [10]
2 years ago
5

Please help !! Will give brainliest :))))

Chemistry
1 answer:
iren2701 [21]2 years ago
4 0

Answer:

3 10 protons 12 neutrons 12 electrons

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4. How many moles of KBr are found in 3 Liters of 0.4 M solution?
Allisa [31]

There are 1.2 moles of KBr found in 3 Liters of 0.4 M solution.

<h3>HOW TO CALCULATE NUMBER OF MOLES?</h3>

The number of moles of a substance can be calculated by multiplying the molarity by the volume.

No. of moles = Molarity × volume

According to this question, 3L of a KBr solution are contained in a 0.4M.

no. of moles = 3L × 0.4M = 1.2moles

Therefore, there are 1.2 moles of KBr found in 3 Liters of 0.4 M solution.

Learn more about no. of moles at: brainly.com/question/14919968

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2 years ago
A path that an electric current followos is a
Fed [463]
The flow of electricity is an electric current. The path that an electric currents floes is a circuit.
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3 years ago
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Which of the following will increase the number of collisions without changing the energy of reactant molecules?
natulia [17]

Answer:increasing the concentration of reactants

Explanation:

Collision is the phenomenon in which the reactant molecules come to nearest closness,as a result the reactants are converted into products.

Now the number of effective collision is directly proportional to the number of reactants added..

6 0
3 years ago
What are the top eight elements found in the Earth’s crust?
rosijanka [135]

Answer: You should learn the symbols for the eight most abundant elements in the Earth's crust (Oxygen (O), Silicon (Si), Aluminum (Al), Calcium (Ca), Iron (Fe), Magnesium (Mg), Sodium (Na), and Potassium (K) .

Explanation:

7 0
2 years ago
Nitrogen and oxygen form an extensive series of oxides with the general formula NxOy. One of them is a blue solid that comes apa
Marizza181 [45]

Work out the number of moles in

100.00 grams of the oxide.

For nitrogen: The atomic mass of N is 14.0067, and we have 36.84 g N:

36.84 g N14.0067 g N/mol N=2.630 mol N

For oxygen: The atomic mass of O is

15.9994, and we have

100.00−36.84=63.16 g O:

63.16 g N 15.9994 g N/mol N=3.948 mol N

Now the ratio 3.958 2.630 is very close to

1.5=32

. So we conclude that the gas has three moles

O to two moles N making the empirical formula

N2O3.

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