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3 years ago

Balance the equation KHCO3+ H3PO4 arrow K2HPO4+H20 C02.

Chemistry

1 answer:

kherson [118]3 years ago

4 0

Answer:

2KHCO3+ H3PO4 arrow K2HPO4 + 2 H20 + 2C02

Explanation:

2KHCO3+ H3PO4 arrow K2HPO4 + 2 H20 + 2C02

Start with the Ks. Don't start on the right. Just balance the Ks on the left. The reason is that the CO3 is going to break down as well.

2KHCO3+ H3PO4 arrow K2HPO4 + H20 + C02

Leave the PO4 alone. Now look at the Hs that are on the right. There are 5 on the left. Leave the K2HPO4 alone. If you put a 2 in front of tthe H2O then you have a total of 5 Hs on the right.

2KHCO3+ H3PO4 arrow K2HPO4 + 2H20 + C02

There are 2 carbons on the left. You need 2 on the right.

2KHCO3+ H3PO4 arrow K2HPO4 + 2H20 + 2C02

That should do it.

Let's make a table to show balance.

Species K H C PO4- O

Left 2 5 2 1 6 from CO3^(2-)

Right 2 5 2 1 6 from H2O/CO2

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4 years ago

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4 years ago

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3 years ago

Describe the differences between groups in the current day Periodic table of elements

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4 years ago

Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: Zn2+, Ni4+, F-

hram777 [196]

Ionic compounds are formed between oppositely charged ions.

A binary ionic compound is composed of ions of two different elements - one of which is a positive ion(metal), and the other is negative ion (nonmetal).

To write the empirical formula of binary ionic compound we must remember that one ion should be positive and other ion should be negative, then only the correct formula should be written. To write the empirical formula the charges of opposite ions should be criss-crossed.

First empirical formula of binary ionic compound is written between $Zn^{2+} (Positive ion)and F^{-} (Negative ion)$

First Formula would be $ZnF_{2}$

Second empirical formula is between $Zn^{2+}(Positive ion) and O^{2-}(Negative ion)$

Second Formula would be $Zn_{2}O_{2}$

Note : When the subscript are same they get cancel out, so $Zn_{2}O_{2}$ would be written as $ZnO$

Third empirical formula is between $Ni^{4+}(Positive ion) and F^{-}(Negative ion)$

Third Formula would be : $NiF_{4}$

Forth empirical formula is between $Ni^{4+}(Positive ion)and O^{2-}(negative ion)$

Forth Formula would be : $Ni_{2}O_{4}$ or $NiO_{2}$

Note- The subscript will be simplified and the formula will be written as $NiO_{2}$ .

The empirical formula of four binary ionic compounds are : $ZnF_{2}, ZnO, NiF_{4},NiO_{2}$

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3 years ago

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