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LenKa [72]
3 years ago
12

(Please answer within 30-35 minutes)

Biology
1 answer:
Doss [256]3 years ago
3 0

Answer:

Explanation:

so

2 breads + 2 cheeses ⇒ 1 sandwich

if we use two slices of bread each time how many sandwich can we make with 33 slices

33/2 =16.5 sandwiches

if we use two pieces of cheese in each sandwiches how many sandwiches can we make with 15 slices ?

15/2 =7.5 sandwiches

the cheese her will run out first and we would have excess bread

so we would only be able to make 7.5 sandwiches without running out of ant ingredient :)

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Cystic fibrosis is most common in individuals of Northern European descent, affecting 1 in 3200 newborns. Assuming that these al
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Answer:

0.0177

Explanation:

Cystic fibrosis is an autosomal recessive disease, thereby an individual must have both copies of the CFTR mutant alleles to have this disease. The Hardy-Weinberg equilibrium states that p² + 2pq + q² = 1, where p² represents the frequency of the homo-zygous dominant genotype (normal phenotype), q² represents the frequency of the homo-zygous recessive genotype (cystic fibrosis phenotype), and 2pq represents the frequency of the heterozygous genotype (individuals that carry one copy of the CFTR mutant allele). Moreover, under Hardy-Weinberg equilibrium, the sum of the dominant 'p' allele frequency and the recessive 'q' allele frequency is equal to 1. In this case, we can observe that the frequency of the homo-zygous recessive condition for cystic fibrosis (q²) is 1/3200. In consequence, the frequency of the recessive allele for cystic fibrosis can be calculated as follows:

1/3200 = q² (have two CFTR mutant alleles) >>  

q = √ (1/3200) = 1/56.57 >>

- Frequency of the CFTR allele q = 1/56.57 = 0.0177  

- Frequency of the dominant 'normal' allele p = 1 - q = 1 - 0.0177 = 0.9823

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