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IRINA_888 [86]
3 years ago
8

Solve for x in the equation x^2 - 8x + 40 = 0​

Mathematics
1 answer:
laiz [17]3 years ago
5 0

Answer:

Conclusion : Trinomial can not be factored

Step-by-step explanation:

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OlgaM077 [116]
28 slices
10 1/2 divided by 3/8 is 28
28 times 3/8 equals 10 1/2
6 0
3 years ago
4) Which linear inequality represents the solution set graphed?
horsena [70]

Answer:

D)€÷√€€$&7$&7$&dy+&"&_

3 0
3 years ago
A team of 5 runners competed in a relay race. Each runner had to run 730 yards. How long was the race? (ANSWER IF YOU KNOW AND H
Naya [18.7K]

Answer:

3650 yds

Step-by-step explanation:

Take the length that each person ran and multiply by the number of runners

5 * 730yds

3650 yds

6 0
3 years ago
Read 2 more answers
Two skateboarders start a race at the same time skateboarder A travels at a steady rate of 15 feet per second skateboarder B tra
Dmitriy789 [7]

Answer:

Step-by-step explanation:

Relative speed can play a major role in creating distance between two bodies. If the relative speed between two bodies is 0, then both the bodies are moving in the same direction with a similar speed. Thus, After 4 minutes, 1680 feet farther will Skateboarder B have traveled.

Skateboarder A travels at a steady rate of 15 feet per second.

Skateboarder B travels at a steady rate of 22 feet per second.

We need to determine that after 4 minutes, how much farther will Skateboarder B have traveled.

The formula for finding the distance travelled by anybody is represented below

Time is given that is 4 minutes which means 240 seconds.

Thus,

Distance travelled by skateboarder A

Distance travelled by skateboarder B.

Therefore, the separation of the distance between both the skateboarders is 5280 - 3600 = 1680.

Thus, After 4 minutes, 1680 feet farther will Skateboarder B have traveled.

7 0
2 years ago
PLEASE PEOPLE, HELP ME!! Geometry
Oksanka [162]
I use the sin rule to find the area

A=(1/2)a*b*sin(∡ab)

1) A=(1/2)*(AB)*(BC)*sin(∡B)
sin(∡B)=[2*A]/[(AB)*(BC)]

we know that
A=5√3
BC=4
AB=5
then

sin(∡B)=[2*5√3]/[(5)*(4)]=10√3/20=√3/2
(∡B)=arc sin (√3/2)= 60°

 now i use the the Law of Cosines 

c2 = a2 + b2 − 2ab cos(C)

AC²=AB²+BC²-2AB*BC*cos (∡B)

AC²=5²+4²-2*(5)*(4)*cos (60)----------- > 25+16-40*(1/2)=21

AC=√21= 4.58 cms

the answer part 1) is 4.58 cms

2) we know that

a/sinA=b/sin B=c/sinC

and

∡K=α

∡M=β

ME=b

then

b/sin(α)=KE/sin(β)=KM/sin(180-(α+β))

KE=b*sin(β)/sin(α)

A=(1/2)*(ME)*(KE)*sin(180-(α+β))

sin(180-(α+β))=sin(α+β)

A=(1/2)*(b)*(b*sin(β)/sin(α))*sin(α+β)=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

KE/sin(β)=KM/sin(180-(α+β))

KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)

the answers part 2) are

side KE=b*sin(β)/sin(α)
side KM=(KE/sin(β))*sin(α+β)
Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

5 0
3 years ago
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