Answer:
0.0143
Step-by-step explanation:
In this question, we are asked to use the binomial distribution to calculate the probability that 10 or fewer passengers from a sample of MIT data project sample were on American airline flights.
We proceed as follows;
The probability that a passenger was an American flight is 15.5%= 15.55/100 = 0.155
Let’s call this probability p
The probability that he/she isn’t on the flight, let’s call this q
q =1 - p= 0.845
Sample size, n = 155
P(X < A) = P(Z < (A - mean)/standard deviation)
Mean = np
= 125 x 0.155
= 19.375
Standard deviation = √npq
= √ (125 x 0.155x 0.845)
= 4.0462
P(10 or fewer passengers were on American Airline flights) = P(X \leq 10)
= P(Z < (10.5 - 19.375)/4.0462)
= P(Z < -2.19)
= 0.0143
Answer:
m(WXY) = 224°
Step-by-step explanation:
Measure of inscribed angle = ½ the measure of intercepted arc
Therefore:
m<C = ½*m(WXY)
112° = ½*m(WXY) (substitution)
Multiply both sides by 2
2*112° = m(WXY)
224° = m(WXY)
m(WXY) = 224°
Answer:
5 hours
Step-by-step explanation:
The total cost is the fee plus the hours* hourly cost
450 = 200+50*h where h is the hours
Subtract 200 from each side
450-200 = 200-200 +50h
250 = 50h
Divide each side by 50
250/50 = 50h/50
5 = h
5 hours
