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daser333 [38]
3 years ago
8

Please answer fast

Mathematics
1 answer:
Levart [38]3 years ago
8 0

Answer:

Yes it is

Step-by-step explanation:

Because

2) x (sqrt 3) times (sqrt 12)

Two is also equivalent to sqrt of 4. The operation may be expressed as,

                                  (sqrt 4) x (sqrt 3) x sqrt (12)

The product is sqrt (144). This gives an answer of 12 and it is rational.

So, the answer is Yes!

Hope this helped! :)

May i have brainliest!

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HELP PLEASE WITH MATH
kifflom [539]
14)NO..... -2x+5y=10.....-2(-3)+5(2)=10.....6+10 is not =10
15)YES......-2x+5y=10....-2(-10)+5(-2)=10.....20-10=10
16)YES......-2x+5y=10.....-2(5)+5(4)=10......-10+20=10
3 0
3 years ago
Someone plz help me out
Musya8 [376]

Answer:

The correct answer is B) - 1/6

Step-by-step explanation:

To find the answer, simply subtract two consecutive values of f(x). Any 2 will give you the same answer.

49/6 - 25/3

49/6 - 50/6

-1/6

8 0
3 years ago
A membership committee of three is formed from four eligible members. let the eligible members be represented by a, b, c, and d.
Lynna [10]

The correct statements are:

There are four ways to choose the committee.

There are three ways to form the committee if person D must be on it.

If persons B and C must be on the committee, there are two ways to form the committee.

It is given that:

A membership committee of three is formed from four eligible members.

1)

There are four ways to choose the committee.

This statement is true.

since we have to choose 3 members out of the 4 members so we can use the method of combination.

2)

There are three ways to form the committee if person D must be on it.

This statement is also true.

since D has to be in the committee, this means we have to choose 2 more people out of the three people to form the committee.

3)

If seven members are eligible next year, then there will be fewer combinations.

This statement is wrong.

Since we have to choose 3 members out of 7 members so the number of possible combinations will be:

i.e. there are 35 combinations possible.

4)

If persons B and C must be on the committee, there are two ways to form the committee.

if B and C have to be in the committee then we have to choose just one person out of the two people left.

Hence, the statement is true.

5)

If persons A and C must be on the committee, then there is only one way to form the committee.

If A and C have to be in the committee then as in last option we have to choose any one of the two person left.

so possible number of ways are 2.

Hence, the statement is false.

Learn more about Combinations:

brainly.com/question/4658834

#SPJ4

3 0
3 years ago
Fill in the table of values for y=x3+x2-6x
AfilCa [17]

Answer:

Step-by-step explanation:

y=5x-6x

y=(-1x)

6 0
3 years ago
find four consecutive even integers such that the sum of the third and fourth is 6 less than four times the first​
lisabon 2012 [21]

Answer:

The numbers are 2, 4, 6 and 8

Step-by-step explanation:

let the four numbers be x, y, z and l respectively

then:

x+y+z+l

(z+l)–6=4x

since they are all four consecutive even integers

then y=x+2

z=y+2=x+4

l=z+2=x+6

since (z+l)–6=4x

then ((x+4)+(x+6))–6=4x

2x+4=4x

4=4x–2x

4=2x

2=x

5 0
3 years ago
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