Find area of trapezoid

Mathematics

2 answers:

DochEvi [55]2 years ago

7 0

Answer:

150 sqaure ft

Step-by-step explanation:

okay so the formula for area of a trapezoid is

1/2 (b1 + b2) h

so base one of 15 plus two of 10 os 25 ft

25 feet divided by 2 is 12.5 so 12.5 × 12 is 150

andre [41]2 years ago

6 0

150 square feet......................

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Rationalise 10/√7-√2

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<h3>Solution:</h3>

$\frac{10}{ \sqrt{7} - \sqrt{2} } \\ = \frac{10}{ \sqrt{7} - \sqrt{2} } \times \frac{ \sqrt{7} + \sqrt{2} }{ \sqrt{7} + \sqrt{2} } \\ = \frac{10( \sqrt{7} + \sqrt{2}) }{( \sqrt{7} - \sqrt{2} )( \sqrt{7} + \sqrt{2} )} \\ = \frac{10 \sqrt{7} + 10 \sqrt{2} }{( { \sqrt{7} )}^{2} - ( \sqrt{2} ) ^{2} } \\ = \frac{10( \sqrt{7} + \sqrt{2} )}{7 - 2} \\ = \frac{10( \sqrt{7} + \sqrt{2} ) }{5} \\ = 2( \sqrt{7} + \sqrt{2} ) \\ = 2 \sqrt{7} + 2 \sqrt{2}$

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2 years ago

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A soccer player heads a ball from a height of 6 feet with an initial vertical velocity of 20 feet per second. The height h in fe

nlexa [21]

WE see that at time t=0 the ball's height is 6 feet so we know the origin of our coordinates is the ground (h=0 feet) So we need to solve this quadratic equation for the value of t that makes the equation 0. There will be 2 solutions, one will be right and the other is usually impossible (all quadratics have two roots)
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2 years ago

BRAINLIESTT ASAP! PLEASE HELP ME :)

Anvisha [2.4K]

Step-by-step explanation:

$\displaystyle y = Asec(Bx - C) + D$

According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:

$\displaystyle Phase\:[Horisontal]\:Shift → \frac{0}{4} = 0 \\ Period → \frac{2}{4}π = \frac{π}{2}$

Therefore we have our answer.

Extended Information on the trigonometric function

$\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|$

NOTE: Sometimes, your vertical shift might tell you to shift your graph below or above the midline where the amplitude is. Moreover, ALL tangent, secant, cosecant, and cotangent functions have NO AMPLITUDE.

I am joyous to assist you anytime.