Height of the woman = 5 ft
Rate at which the woman is walking = 7.5 ft/sec
Let us assume the length of the shadow = s
Le us assume the <span>distance of the woman's feet from the base of the streetlight = x
</span>Then
s/5 = (s + x)/12
12s = 5s + 5x
7s = 5x
s = (5/7)x
Now let us differentiate with respect to t
ds/dt = (5/7)(dx/dt)
We already know that dx/dt = 7/2 ft/sec
Then
ds/dt = (5/7) * (7/2)
= (5/2)
= 2.5 ft/sec
From the above deduction, it can be easily concluded that the rate at which the tip of her shadow is moving is 2.5 ft/sec.
Answer by JKismyhusbandbae: B) –10.6
Work/Explanation: Since the sequence slowly gets smaller, it is likely that each term is something added to (subtracted from) the previous term. To get from –7.9 to –8.8, it appears that the first has had –0.9 added to it. Continue adding –0.9 to get that the fourth term is –10.6.
Answer:
1,041.9feet
Step-by-step explanation:
Given the height of the rocket expressed as
y = -16x² + 245x + 104
At maximum height, dy/dx = 0
dy/dx = -32x+245
0 = -32x+245
32x = 245
x = 245/32
x = 7.65625
Get the maximum height
Recall that;
y = -16x² + 245x + 104
Substitute the value of x;
y = -16(7.65625)² + 245(7.65625) + 104
y = -937.890625 + 1,875.78125 + 104
y = 1,041.890625feet
Hcne the maximum height to the nearest foot is 1,041.9feet
Answer:
I think its will be B
Step-by-step explanation:
