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SOVA2 [1]
3 years ago
9

What is the probability of the offspring having brown eyes (dominant) if the father has the "bb" genotype and the mother has the

"BB" genotype? You must create your own Punnett Square. *
Biology
1 answer:
nikdorinn [45]3 years ago
7 0

Answer:

1 or 100%

Explanation:

Assuming that the allele B (brown) is dominant over the allele b, crossing the father and the mother:

          BB    x    bb

      Bb    Bb    Bb    Bb (you can also see the Punnet's square)

All the offspring would exhibit the dominant phenotype which is brown. Hence, the probability of the offspring having brown eyes is 100% or simply 1.

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In Oompa Loompas, gray face (G) is dominant to orange recessive face (g). If two gray faced Oompas have an offspring with an ora
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Answer:

The genotype for each of the parents must be

parent 1 : Gg

parent 2 : Gg

Explanation:

Please note that a dominant trait is a trait that is expressed phenotypically in a heterozygous state, while a recessive trait is a trait that can only be expressed in a homozygous state.

Now, since gray face (G) for Oompa Loompas is dominant, and orange face (g) is recessive, for an offspring to be orange faced, it means that the genotype of the offspring must be 'gg'. Also, since both parent contribute an allele in the pair of alleles in the offspring, both parents must have the recessive (g) in their genotype. Moreover, we are told that both parents are gray-faced, meaning that their genotypes were 'Gg' and 'Gg'. To confirm, let me do the cross

                                 G           g

G                                GG       Gg

g                                 Gg        gg

from the cross above, we find out that out of 4 offspring, 3 were gray face (GG, Gg ) while one was orange face (gg).

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