Play made a recipe with 22 cups of liquid total 12 of which were fruit punch

The formula for the slant height of a cone is , where S is surface area of the cone. Use the formula to find the slant height, l

liq [111]

we know that

The formula of the surface area of the cone is equal to

$SA=\pi r^{2}+\pi rl$

where

SA is the surface area

r is the radius of the cone

l is the slant height

in this problem we have

$SA=500\pi\ ft^{2}\\r=15\ ft\\l=?$

Solve the formula for l

$SA=\pi r^{2}+\pi rl\\ \\\pi rl=SA-\pi r^{2} \\ \\l=\frac{SA-\pi r^{2} }{\pi r}$

substitute the values

$l=\frac{500\pi -\pi 15^{2} }{\pi15}\\ \\l=\frac{275}{15}\ ft\\ \\l=\frac{55}{3}\ ft\\ \\l=18\frac{1}{3}\ ft$

therefore

the answer is

The slant height is $18\frac{1}{3}\ ft$

7 0

3 years ago

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In most microcomputers the addresses of memory locations are specified in hexadecimal. These addresses are sequential numbers th

iren [92.7K]

Considering that the addresses of memory locations are specified in hexadecimal.

a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ ) = 65536 memory locations

b) The range of hex addresses in a microcomputer with 4096 memory locations is ; 4095

applying the given data :

a) first step : convert FFFF₁₆ to decimal ( note F₁₆ = 15 decimal )

( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )

= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )

= 61440 + 3840 + 240 + 15 = 65535

∴ the memory locations from 0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations

b) The range of hex addresses with a memory location of 4096

= 0000₁₆ to FFFF₁₆ = 0 to 4096

∴ the range = 4095

Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.

Learn more : brainly.com/question/18993173

6 0

3 years ago

Which expressions are equivalent when m = 1 and m = 4?

s344n2d4d5 [400]

Answer:

expression 2

Step-by-step explanation:

<h2>Which expressions are equivalent when m = 1 and m = 4?</h2>

<h3>first expression:</h3>

5m -3 and 2m + 5 + m

when m = 1

5(1) - 3 = 2 and 2(1) + 5 + 1 = 8

and m = 4

5(4) -3 =23 and 2(4) + 5 + 4 = 17

expression 1 IS NOT EQUIVALENT

<h3>second expression :</h3>

3 m + 4 and m + 4 + 2 m

when m = 1

3 (1) + 4 = 7 and 1 + 4 +2 (1) = 7

and m = 4

3 (4) + 4 = 16 and 4 + 4 +2 (4) = 16

expression 2 IS EQUIVALENT

<h3>third expression :</h3>

2 m + 7 and 3 m - 3 + m

when m = 1

2(1) + 7 = 9 and 3(1) -3 + 1 = 1

and m = 4

2(4) + 7 = 15 and 3(4) -3 + 4 = 13

expression 3 IS NOT EQUIVALENT

<h3>fourth expression :</h3>

5 m + 3 and 4 m + 2 + 2 m

when m = 1

5(1)+ 3 = 8 and 4(1) + 2 +2(1) = 8

and m = 4

5(4)+ 3 = 23 and 4(4) + 2 +2(4) = 26

expression 4 is NOT EQUIVALENT

the expression that is EXPRESSION 2

8 0

3 years ago

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Integration of (cosec^2 x-2005)÷cos^2005 x dx is

kondor19780726 [428]

We are asked in the problem to evaluate the integral of (cosec^2 x-2005)÷cos^2005 x dx. The function is an example of a complex function with a degree that is greater than one and that uses special rules to integrate the function via the trigonometric functions. For example, we integrate
2005/cos^2005x dx which is equal to 2005 sec^2005 x since sec is the inverse of cos. The integral of this function when n >3 is equal to I=∫sec(n−2)xdx+∫tanxsec(n−3)x(secxtanx)dx
Then,
∫tanxsec(n−3)x(secxtanx)dx=tanxsec(n−2)x/(n−2)−1/(n−2)I
we can then integrate the function by substituting n by 3.

On the first term csc^2 2005x / cos^2005 x we can use the trigonometric identity csc^2 x = 1 + cot^2 x to simplify the terms

7 0

3 years ago

My question is

Eduardwww [97]

So 2 gallons every 5 minutes
2/5= .4
so .4 a minute
and you already have 5 gallons in so those need to be added
m=minutes
y=0.4m + 5 will be what you want to find out if you are looking to find out how much will be there in a certain time
for 50 minutes you will have
y=0.4(50) +5
20+5
25 gallons
HOWEVER, the equation has to be changed if you want to tell how long you have to wait for it to fill.
m=2.5(g-5)
m=minutes
g= gallons
you subtract 5 because they are already there
you multiply by 2.5 because it fills at a rate of 1 gallon every 2.5 minutes.
m=2.5(1500-5)
for the sake of it being easier i will do the -5 separately
2.5(1500 = 3750
2.5(-5= -12.5
3750-12.5
3737.5 minutes to fill the pool.
3720/60 = 62
17.5/60 = .292
62.292 hours to fill the pool.
p.s. you have a really slow hose.
Its good you didn't wait for it to fill, you would have died from lack of water before then if you just sat and waited.

3 0

3 years ago

Play made a recipe with 22 cups of liquid total 12 of which were fruit punch​

Play made a recipe with 22 cups of liquid total 12 of which were fruit punch