3 years ago

Imágenes de angulos segun su posicion

Mathematics

1 answer:

Katen [24]3 years ago

7 0

Imágenes de angulos segun su posicion
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The nth term of a sequence is 3n squared. What is the 15th term

BabaBlast [244]

Answer:

2025

Step-by-step explanation:

3n² is our nth term

n=15

thus....

(3×15)²

= 45²=2025

Hopefully this helped- have a great day)

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2 years ago

The answer to this problem?

LenaWriter [7]

The simplified expression of $\sqrt{\frac{162x^9}{2x^{27}}}$ is $\frac{9}{x^9}$

<h3>How to simplify the expression?</h3>

The expression is given as:

$\sqrt{\frac{162x^9}{2x^{27}}}$

Divide 162 and 2 by 2

$\sqrt{\frac{81x^9}{x^{27}}}$

Take the square root of 81

$9\sqrt{\frac{x^9}{x^{27}}}$

Apply the quotient rule of indices

$9\sqrt{\frac{1}{x^{27-9}}}$

Evaluate the difference

$9\sqrt{\frac{1}{x^{18}}}$

Take the square root of x^18

$\frac{9}{x^9}$

Hence, the simplified expression of $\sqrt{\frac{162x^9}{2x^{27}}}$ is $\frac{9}{x^9}$

Imágenes de angulos segun su posicion​

Imágenes de angulos segun su posicion