The poverty level cutoff in 1987 to the nearest dollar was $10787.
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How to find a midpoint?</h3>
The midpoint as the point that divides the line segment exactly in half having two equal segments. Therefore, the midpoint presents the same distance between the endpoints for the line segment. The midpoint formula is:
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For solving this exercise, first you need plot the points in a chart. See the image.
Your question asks to approximate the poverty level cutoff in 1987 to the nearest dollar using the midpoint formula. Note that the year 1987 is between 1980 and 1990, thus you should apply the midpoint formula from data for this year (1987).
![\mathrm{Midpoint\:of\:}\left(1980,8429),\:\left(1990,13145):\quad \left(\frac{1990+1980}{2},\:\:\frac{13145+8429}{2}\right)\\\\ \\](https://tex.z-dn.net/?f=%5Cmathrm%7BMidpoint%5C%3Aof%5C%3A%7D%5Cleft%281980%2C8429%29%2C%5C%3A%5Cleft%281990%2C13145%29%3A%5Cquad%20%5Cleft%28%5Cfrac%7B1990%2B1980%7D%7B2%7D%2C%5C%3A%5C%3A%5Cfrac%7B13145%2B8429%7D%7B2%7D%5Cright%29%5C%5C%5C%5C%20%5C%5C)
![\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\left(\frac{1990+1987}{2},\:\frac{13145+3843}{2}\right)\\ \\ =\left(\frac{3977}{2},\:\frac{21574}{2}\right)](https://tex.z-dn.net/?f=%5Cmathrm%7BMidpoint%5C%3Aof%5C%3A%7D%5Cleft%281980%2C8429%29%5C%3A%3D%5Cleft%28%5Cfrac%7B1990%2B1987%7D%7B2%7D%2C%5C%3A%5Cfrac%7B13145%2B3843%7D%7B2%7D%5Cright%29%5C%5C%20%5C%5C%20%3D%5Cleft%28%5Cfrac%7B3977%7D%7B2%7D%2C%5C%3A%5Cfrac%7B21574%7D%7B2%7D%5Cright%29)
![\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\=(\frac{3977}{2},10787)](https://tex.z-dn.net/?f=%5Cmathrm%7BMidpoint%5C%3Aof%5C%3A%7D%5Cleft%281980%2C8429%29%5C%3A%3D%5C%3D%28%5Cfrac%7B3977%7D%7B2%7D%2C10787%29)
The answer for your question will be the value that you calculated for the y-coordinate. Then, the poverty level cutoff in 1987 to the nearest dollar was $10787.
Read more about the midpoint segment here:
brainly.com/question/11408596
The answer is commutative property of addition
Answer:
8/15
Step-by-step explanation:
The balls are numbered 3 through 17, so there are 17 − 3 + 1 = 15 balls. 8 of them are odd and 7 of them are even.
So the probability of an odd numbered ball (which includes the number 11 ball) is 8/15.
x+(x+2)=116. Simplify that to 2x+2=116, subtract 2 from both sides to get 2x=114, and then divide both sides by 2 to get x=57. That would be the first integer, so the second would then be 59. So there's your answer: The two consecutive odd integers are 57 and 59.Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
256 = 16×16=4×4×4×4 = 4^4
X^4-4^4 = (x^2)^2 - (4^2)^2
Using algebraic identity a^2-b^2 = (a+b)(a-b)
We get (x^2+4^2)(x^2-4^2)
(x^2+4^2)(x+2)(x-2)