Answer:Serkan teacher regularly buys 75 TL of gasoline in his car every week.
At the end of the 13th week, how much is the total gasoline expenditure made by the serkan teacher?
A)390 B)420 C)900 D)975
Step-by-step explanation:
Answer:
N = 52 * (9/7)^(t/1.5)
Step-by-step explanation:
This problem can be modelated as an exponencial problem, using the formula:
N = Po * (1+r)^(t/1.5)
Where P is the final value, Po is the inicial value, r is the rate and t is the amount of time.
In our case, we have that N is the final number of branches after t years, Po = 52 branches, r = 2/7 and t is the number of years since the beginning (in the formula we divide by 1.5 because the rate is defined for 1.5 years)
Then, we have that:
N = 52 * (1 + 2/7)^(t/1.5)
N = 52 * (9/7)^(t/1.5)
Not very much because things don't always happen the way we want them too
Answer:
{7x^2+168x+840}/{x+12}
Step-by-step explanation:
Answer:
Step-by-step explanation:
It’s a repeating pattern.
i² = -1
i³ =(i²)i = (-1)i = -i
i⁴ = i³i = -i² = 1
i⁵ = (i⁴)i = (1)i = i
i⁶ = i⁵i = i² = -1
...
i¹⁷ = i
