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Komok [63]
3 years ago
12

The distance an object falls when dropped from a tower varies directly as the square of the time it falls. If the object falls 1

44 feet in 3 seconds, how far will it fall in 17 seconds? a 4046 ft b 272 ft c 4624 ft d 5202 ft answer is C​
Mathematics
2 answers:
USPshnik [31]3 years ago
4 0

Step-by-step explanation:

Assuming the Height is denoted by "h" and the time by "t" , h=kt² since h varies as t².

When h=144ft , t=3

k=h/t²

k=144/3²

k= 16

This implies that h=16t² is the relation to be used.

Therefore when t= 17s, h=16*17²

h=4624ft

Tanzania [10]3 years ago
3 0

Answer:

the object will fall 792 feet in 17 seconds

Step-by-step explanation:

first you can do 144 multiplied by 5 because that would be 15 of those seconds next you would do 144 divided by 2 because you only need 2 seconds to reach 17 your answer would be 72 then you would do 720+72=792 so it would fall 792ft in 17 seconds

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Steve is buying a sandwich for lunch and some fresh fruit juice for his friends. The sandwich costs $3.92 and the fruit juice co
Svetradugi [14.3K]

Answer:

D

Step-by-step explanation

2+2-4

4 0
4 years ago
Ivana printer prints 40 pages in 5 minutes.How many pages will the printer print in 8 minutes
Lana71 [14]

64 pages

divide 40 by 5 for pages printed in 1 minute then multiply this by 8

\frac{40}{5} × 8 = 8 × 8 = 64 pages


6 0
4 years ago
Read 2 more answers
When a cube with sides numbered one through six is roll one time what is the probability of rolling a four or greater?
Elanso [62]
Since it's a six dice then it's out of x/6

How much is 4 to 6 ?

~3 (counting 4) 4.5.6...

So it's 3/6 = 1/2

3 0
4 years ago
Read 2 more answers
Assume the hold time of callers to a cable company is normally distributed with a mean of 5.5 minutes and a standard deviation o
Ierofanga [76]

Answer:

The percent of callers are 37.21 who are on hold.

Step-by-step explanation:

Given:

A normally distributed data.

Mean of the data, \mu = 5.5 mins

Standard deviation, \sigma = 0.4 mins

We have to find the callers percentage who are on hold between 5.4 and 5.8 mins.

Lets find z-score on each raw score.

⇒ z_1=\frac{x_1-\mu}{\sigma}   ...raw score,x_1 = 5.4

⇒ Plugging the values.

⇒ z_1=\frac{5.4-5.5}{0.4}

⇒ z_1=-0.25  

For raw score 5.5 the z score is.

⇒ z_2=\frac{5.8-5.5}{0.4}  

⇒ z_2=0.75

Now we have to look upon the values from Z score table and arrange them in probability terms then convert it into percentages.

We have to work with P(5.4<z<5.8).

⇒ P(5.4

⇒ P(-0.25

⇒ P(z

⇒ z(1.5)=0.7734 and z(-0.25)=0.4013.<em>..from z -score table.</em>

⇒ 0.7734-0.4013

⇒ 0.3721

To find the percentage we have to multiply with 100.

⇒ 0.3721\times 100

⇒ 37.21 %

The percent of callers who are on hold between 5.4 minutes to 5.8 minutes is 37.21

4 0
3 years ago
Can you help me please ​
Olenka [21]

Answer:

log_372 = 3.8928

Step-by-step explanation:

Given

log_38 = 1.8928

Required

Evaluate log_372

We have:

log_372 = log_3(8 *9)

Apply law of logarithm

log_372 = log_38 +log_39

Express 9 as 3^2

log_372 = log_38 +log_33^2

Evaluate the exponents

log_372 = log_38 +2log_33

log_33 = 1.

So:

log_372 = log_38 + 2 * 1

log_372 = log_38 + 2

Substitute log_38 = 1.8928

log_372 = 1.8928 + 2

log_372 = 3.8928

5 0
3 years ago
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