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3 years ago

Solve for x : 8(2x + 3) = -2x + 96

Mathematics

1 answer:

wolverine [178]3 years ago

5 0

Answer:

Isolate the variable by dividing each side by factors that don't contain the variable.

x = 4

Step-by-step explanation:

Hope this helps! Have a nice day and Brainliest please

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Inez says you can plot 4/0 on a number line, but Jeremiah says you cannot. Who is correct?

Vera_Pavlovna [14]

Answer:

Jeremiah.

Step-by-step explanation:

Anything divided by 0 is undefined. There is no such number that can be divisible by 0.

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3 years ago

The table lists average monthly temperatures and electricity cost for a Texas home in 2008. The table displays the value rounded

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The scatter plot describes a linear relationship.

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3 years ago

In the equation below, for what value of c does x = 4?<br> 1 / (2x + 4) = 3x-c

rodikova [14]

Answer:

Option D.

Jenn's answer is not correct. She got it substituting $c=4$ into the equation and solving for "x".

Step-by-step explanation:

Given the following equation:

$\frac{1}{2}(2x + 4) = 3x-c$

Since you need that $x=4$ , you hace to substitute that value into the equation:

$\frac{1}{2}(2(4) + 4) = 3(4)-c$

Now you need to solve for "c":

$\frac{1}{2}(8 + 4) = 12-c\\\\\frac{12}{2}= 12-c\\\\6=12-c\\\\c+6=12\\\\c=12-6\\\\c=6$

Therefore for a a value of $c=6$ , you get $x=4$

Then, the you can identify that the correct answer is the one given in the Option D.

Jenn made a mistake, because she substituted $c=4$ into the equation and then solve for "x":

$\frac{1}{2}(2x + 4) = 3x-(4)\\\\x+2=3x-4\\\\2+4=3x-x\\\\6=2x\\\\\frac{6}{2}=x\\\\x=3$

3 0

3 years ago

Over the summer, for every 14 okra seeds Dana planted, 9 grew into plants. If he planted 210 okra seeds, how many grew into plan

Katena32 [7]

210s(9p/14s)=135p

So 135 seeds grew into plants.

8 0

4 years ago

Read 2 more answers

Complete each congruence statement by naming the corresponding angle or side (odd questions only)

Oksi-84 [34.3K]

Given:

1. $\Delta HJI\cong \Delta IQP$

3. $\Delta JLK\cong \Delta FGH$

To find:

The missing values to complete the congruence statements:

1. $\overline{IH}\cong \_\_\_\_$

3. $\angle KJL\cong \_\_\_\_\_$

Solution:

We have,

$\Delta HJI\cong \Delta IQP$

Here, vertices H, J, I are corresponding to I, Q, P. So,

$\overline{IH}\cong \overline{PI}$

Therefore, the complete statement is $\overline{IH}\cong \overline{PI}$ .

We have,

$\Delta JLK\cong \Delta FGH$

Here, vertices J, L, K are corresponding to F, G, H. So,

$\angle KJL\cong \angle HFG$

Therefore, the complete statement is $\angle KJL\cong \angle HFG$ .

4 0

3 years ago