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Darina [25.2K]
3 years ago
5

50000+2019 solve me this question asap

Mathematics
2 answers:
HACTEHA [7]3 years ago
4 0
Ay isn’t it just 52019
aleksklad [387]3 years ago
3 0

Answer:

52019

Step-by-step explanation:

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The beginning inventory at cost is $80,000.00 and at retail is $100,000.00. Purchases at cost are $160,000.00 and the retail val
DaniilM [7]

Cost of goods available for is equal

80000+160000=240000

Retail value is equal

100000+200000=300000


This means that the cost of goods sold is 80% (240000÷300000) and gross profit is 20%


Sales= 250000 and it's cost is equal 200000 (250000×0.8)


Ending inventory

=240000-200000=40000...answer


Hope it helps!



6 0
4 years ago
Find the y-intercept for the line represented by this equation.
sashaice [31]

Answer:

A) (0,0)

Step-by-step explanation:

1.) graph the equation, 3x+2y = x+y

2.) the line intersects (0,0) on the coordinate plane

5 0
3 years ago
Pleaseee help me with THISS please
marta [7]

Answer:

65.1

Step-by-step explanation:

FG corresponds to IJ, and EF corresponds to HI. So, 13/47 = 18/x. 13x = 846, x= 65.08, which rounds to 65.1.

6 0
3 years ago
Do I reflect if up word or to the left? Help please
givi [52]

Answer:

Upward

Step-by-step explanation:

On a standard graph, the horizontal line is the x-axis and thr vertical is the y-axis

3 0
2 years ago
Solve the following equation simultaneously 1/x-5/y=7, 2/x+1/y=3​
maria [59]

Answer:

  (x, y) = (1/2, -1)

Step-by-step explanation:

Subtracting twice the first equation from the second gives ...

  (2/x +1/y) -2(1/x -5/y) = (3) -2(7)

  11/y = -11 . . . . simplify

  y = -1 . . . . . . . multiply by y/-11

Using the second equation, we can find x:

  2/x +1/-1 = 3

  2/x = 4 . . . . . . . add 1

  x = 1/2 . . . . . . . multiply by x/4

The solution is (x, y) = (1/2, -1).

_____

<em>Additional comment</em>

If you clear fractions by multiplying each equation by xy, the problem becomes one of solving simultaneous 2nd-degree equations. It is much easier to consider this a system of linear equations, where the variable is 1/x or 1/y. Solving for the values of those gives you the values of x and y.

A graph of the original equations gives you an extraneous solution of (x, y) = (0, 0) along with the real solution (x, y) = (0.5, -1).

6 0
3 years ago
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