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Alona [7]
3 years ago
11

Please help me thanks please

Mathematics
1 answer:
Brrunno [24]3 years ago
7 0

Answer:

q = (16 / √2) or 8√2

Step-by-step explanation:

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Helppp! idk why its needs to be 20 charactes so i wrote this
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This should be 1.35, sorry if it’s wrong
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COSO ---
Vsevolod [243]

Answer:

• zero: -4, -4/3, 7

• positive: -4 < x < -4/3 . . . or 7 < x

• negative: x < -4 . . . or -4/3 < x < 7

Step-by-step explanation:

Zeros of the function are at x=-4, -4/3, +7. These are the values that make each of the individual factors be zero. For example, x-7=0 when x=7.

The function will be negative for x-values left of an odd number of zeros. It will be positive for x-values left of an even number of zeros (including left of no zeros, which is to say right of all zeros). This is because the sign of the factor giving rise to the zero changes for x-values on either side of that zero. (This is not true for zeros with even multiplicity, as the sign does not change at those.)

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3 years ago
The exponentia growth model A=30e^.198026t describes the population by what % is the population of the city increasing each year
Artyom0805 [142]
<span>A=30e^.198026t
= </span><span>30(e^.198026)^t
= 30(1.218994087)^t

approximately 21.90% every year
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8 0
3 years ago
Evaluate the expression when f=6 12f+3
Ratling [72]

Answer:

75

Step-by-step explanation:

Substitute 6 for f

12f+3=

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A spherical balloon is inflated so that its volume is increasing at the rate of 3 ft3/min. How fast is the diameter of the ballo
beks73 [17]

When an spherical balloon volume is increasing at the rate of 3ft^3/min then the diameter of the balloon is increasing \frac{3}{2\pi }ft /min

How can we find the rate of change of balloon's diameter ?

The volume of a spherical balloon is v=\frac{4}{3} \pi r^3

In form of diameter we can write as

v=\frac{4}{3} \pi (\frac{D}{2} )^3\\=\frac{1}{6} \pi D^3

Now we will differentiate both sides wrt to t we get

\frac{dv}{dt} =\frac{1}{6} \pi 3D^2 \frac{dD}{dt} \\\frac{dD}{dt} =\frac{2}{\pi D^2} \frac{dv}{dt} \\\\when r=1\\D=2ft

Given in the question \frac{dv}{dt} =3ft^3/min

thus when we substitute the values we get

\frac{dD}{dt} =\frac{2}{\pi *2^2} (3)\\\frac{dD}{dt}=\frac{3}{2\pi }  ft/min

Learn more about the differentiation here:

brainly.com/question/28046488

#SPJ4

3 0
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