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zheka24 [161]
3 years ago
13

Quadrilateral ABCD is a rhombus. suppose measure of angle A decreases. Which of the following changes woukd also need to happen

in order for ABCD to still be a rhombus
Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
6 0
Assuming the side lengths did not change, ...

Angle C would need to decrease by the same amount.
Angles B and D would each need to increase by the amount angle A decreased.
ad-work [718]3 years ago
6 0

Answer:

Step-by-step explanation:

Given that quadrilateral ABCD is a rhombus.  Given that angle A decreases.

Since nothing is mentioned about the side of the rhombus, we see that side is not changing.

When angle A decreases, since opposite angles are congruent we must have equal decrease in C

Also opposite sides are parallel in a rhombus, hence adjacent angles are supplementary.

i.e. Whenever A decreases by a quantity say p, then B and D, the adjacent angles must increase by same quantity p so that the parallel lines property is preserved in the rhombus.

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When n is small (less than 30), how does the shape of the t distribution compare to the normal distribution?
Anna [14]

When n is small (less than 30), how does the shape of the t distribution compare to the normal distribution then"it is flatter and wider than the normal distribution."

<h3>What is normal distribution?</h3>

The normal distribution explains a symmetrical plot of data around the mean value, with the standard deviation defining the width of the curve. It is represented graphically as "bell curve."

Some key features regarding the normal distribution are-

  • The normal distribution is officially known as the Gaussian distribution, but the term "normal" was coined after scientific publications in the nineteenth century demonstrated that many natural events emerged to "deviate normally" from the mean.
  • The naturalist Sir Francis Galton popularized the concept of "normal variability" as the "normal curve" in his 1889 work, Natural Inheritance.
  • Even though the normal distribution is a crucial statistical concept, the applications in finance are limited because financial phenomena, such as expected stock-market returns, do not fit neatly within a normal distribution.
  • In fact, prices generally follow a right-skewed log-normal distribution with fatter tails.

As a result, relying as well heavily on the a bell curve when forecasting these events can yield unreliable results.

To know more about the normal distribution, here

brainly.com/question/23418254

#SPJ4

6 0
1 year ago
Earth, Mars, Saturn, Uranus and Neptune revolve around the sun. Earth takes 1 year, Mars 2 years, Saturn 30 years, Uranus 84 yea
Anettt [7]

Answer:

  30 years

Step-by-step explanation:

2 is a factor of 30, so the LCM of 2 and 30 is 30.

Saturn and Mars will appear in the same direction in the night sky every 30 years.

3 0
3 years ago
Find the indicated probability. The weekly salaries of teachers in one state are normally distributed with a mean of $490 and a
Alecsey [184]

Given Information:

Mean weekly salary = μ = $490

Standard deviation of weekly salary = σ = $45

Required Information:

P(X > $525) = ?

Answer:

P(X > $525) = 21.77%

Step-by-step explanation:

We want to find out the probability that a randomly selected teacher earns more than $525 a week.

P(X > 525) = 1 - P(X < 525)\\\\P(X > 525) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\P(X > 525) = 1 - P(Z < \frac{525 - 490}{45} )\\\\P(X > 525) = 1 - P(Z < \frac{35}{45} )\\\\P(X > 525) = 1 - P(Z < 0.78)\\\\

The z-score corresponding to 0.78 from the z-table is 0.7823

P(X > 525) = 1 - 0.7823\\\\P(X > 525) = 0.2177\\\\P(X > 525) = 21.77 \%

Therefore, there is 21.77% probability that a randomly selected teacher earns more than $525 a week.

How to use z-table?

Step 1:

In the z-table, find the two-digit number on the left side corresponding to your z-score. (e.g 0.7, 2.2, 1.5 etc.)

Step 2:

Then look up at the top of z-table to find the remaining decimal point in the range of 0.00 to 0.09. (e.g. if you are looking for 0.78 then go for 0.08 column)

Step 3:

Finally, find the corresponding probability from the z-table at the intersection of step 1 and step 2.

3 0
3 years ago
Need help with this problem for my cousin
yKpoI14uk [10]
You have separated the figure into three (3) parts. There are two squares (or rectangles on the bottom. Subtract 5 from 8 to find out the length of the side (right side). 8-5=3. Then subtract 3 from 8 (8-3=5). The new length is 5 ft. 5 multiplied by 5 is the area of one of the squares on the bottom (25 ft. squared). Multiply that by two to find the area of both the squares on the bottom (50 ft. squared).

There's also a rectangle on the top. The base is 15 ft. and the height is 3 ft. Remember that you subtracted 5 from 8 to find out the area of the two bottom squares. 15 multiplied by 3 is 45 (ft.)

Add 45 to 50 to get the area of the entire figure. (45+50=95 or 95 ft. squared).

95 ft. squared is the area of the entire figure. Hope this helped you.
3 0
3 years ago
What is the angle in part c? Thank you.
Anton [14]
It looks like an equilateral triangle if I am correct then angle C equals 60 degrees
7 0
3 years ago
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