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3 years ago

If sec(x)=25/24, find cotangent (x)

Mathematics

1 answer:

nadezda [96]3 years ago

8 0

The answer is 1.042 because you have to divide 25 by 24

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Answer:

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2 years ago

An author signed copies of her newest book for 57 minutes until the bookstore closed at 5:00 What time did the author begin sign

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Answer:

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Step-by-step explanation:

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3 years ago

If y2 = x3 + 2, which statement is true? The equation is a function at all values of x. The equation is not a function. The equa

tatyana61 [14]

Answer:

The equation is not a function.

Step-by-step explanation:

We are given that

$y^2=x^3+2$

$y=\pm\sqrt{x^3+2}$

Function: It is mapping between the values of two sets A and B.

Each element of A has unique value in set B.

By definition of function

In given function

y has no unique value for each value of x.

Substitute x=0

$y=\pm \sqrt{0+2}=\pm \sqrt 2$

Hence, it is not a function.

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3 years ago

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3 years ago

Read 2 more answers

∫(cosx) / (sin²x) dx

kirza4 [7]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2822772

_______________

Evaluate the indefinite integral:

$\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx}\\\\\\
=\mathsf{\displaystyle\int\! \frac{1}{(sin\,x)^2}\cdot cos\,x\,dx\qquad\quad(i)}$

Make the following substitution:

$\mathsf{sin\,x=u\quad\Rightarrow\quad cos\,x\,dx=du}$

and then, the integral (i) becomes

$=\mathsf{\displaystyle\int\! \frac{1}{u^2}\,du}\\\\\\
=\mathsf{\displaystyle\int\! u^{-2}\,du}$

Integrate it by applying the power rule:

$\mathsf{=\dfrac{u^{-2+1}}{-2+1}+C}\\\\\\
\mathsf{=\dfrac{u^{-1}}{-1}+C}\\\\\\
\mathsf{=-\,\dfrac{1}{u}+C}$

Now, substitute back for u = sin x, so the result is given in terms of x:

$\mathsf{=-\,\dfrac{1}{sin\,x}+C}\\\\\\
\mathsf{=-\,csc\,x+C}$

$\therefore~~\boxed{\begin{array}{c}\mathsf{\displaystyle\int\! \frac{cos\,x}{sin^2\,x}\,dx=-\,csc\,x+C} \end{array}}\qquad\quad\checkmark$

I hope this helps. =)

Tags: <em>indefinite integral substitution trigonometric trig function sine cosine cosecant sin cos csc differential integral calculus</em>

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3 years ago