When a number is 3 times a first number. A third number is 100 more than the first number and the sum of the three numbers is 450, the numbers are 70, 170 and 210.
<h3>How to calculate the numbers?</h3>
Let the first number = x
Second number = 3x
Third number = x + 100
Sum = 450
The numbers will be:
x + 3x + x + 100 = 450
5x + 100 = 450
5x = 450 - 100
5x = 350
Divide
x = 350 / 5
x = 70
First number = 70
Second number = 3x = 3 × 70 = 210
Third number = x + 100 = 70 + 100 = 170
Therefore, the numbers are 70, 170 and 210.
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One number is 3 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 450 , find the numbers.
Step-by-step explanation: use a histograph
Answer:
x=85
Step-by-step explanation:
Hope this helps you :))
(Hope it doesn't get reported becuase it "doesn't have an explanation of how it's right") Have a blessed day ^-^
Answer:
0
Step-by-step explanation:
Find the following limit:
lim_(x->∞) 3^(-x) n
Applying the quotient rule, write lim_(x->∞) n 3^(-x) as (lim_(x->∞) n)/(lim_(x->∞) 3^x):
n/(lim_(x->∞) 3^x)
Using the fact that 3^x is a continuous function of x, write lim_(x->∞) 3^x as 3^(lim_(x->∞) x):
n/3^(lim_(x->∞) x)
lim_(x->∞) x = ∞:
n/3^∞
n/3^∞ = 0:
Answer: 0
Answer:
you gave no facts :/
Step-by-step explanation:
