A triangle is a three-edged polygon with three vertices. ΔAKE and ΔCKP are congruent.
<h3>What is a triangle?</h3>
A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. The sum of all the angle of a triangle is always equal to 180°.
In ΔABC, since AB≅BC, therefore, the triangle will be an isosceles triangle, and the measure of ∠A ≅ ∠C, using the base angle theorem.
Now In ΔAKE and ΔCKP,
∠A ≅ ∠C {Proved above}
∠AKE ≅ ∠CKP {Given}
AK ≅ KC {Given }
Since two angles and a side of the triangle are equal, therefore, we can write the two triangle are congruent using the Side-angle-side or Angle-Side-Angle congruence.
Hence, ΔAKE and ΔCKP are congruent.
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Answer:
the pennies does not conform to the US mints specification
Step-by-step explanation:
z = (variate -mean)/ standard deviation
z= 2.5 - 2.4991 / 0.01648 = 0.0546
we are going to check the value of z in the normal distribution table, which is the table bounded by z.
checking for z= 0.0 under 55 gives 0.0219 (value gotten from the table of normal distribution)
we subtract the value of z from 0.5 (1- (0.5+0.0219)) = 0.4781 > 0.05claim
since 0.4781 > 0.05claim, therefore, the pennies does not conform to the US mints specification
the claim state a 5% significance level whereas the calculated significance level is 47.81%. therefore, the claim should be rejected
Answer: 4/3
Step-by-step explanation:
You would find this answer because if x is 0 then it is just 2 then when you multiply 3 x 4/3 you get 4 then when you add that by two you get 6
Hopes this helps
Answer:
The 95% confidence interval for the mean is between 0.985g/cm² and 1.047 g/cm².
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find M as such

In which
is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the mean subtracted by M. So it is 1.016 - 0.0310 = 0.985 g/cm²
The upper end of the interval is the mean added to M. So it is 1.016 + 0.0310 = 1.047 g/cm²
The 95% confidence interval for the mean is between 0.985g/cm² and 1.047 g/cm².