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3 years ago

Question below thanks

Mathematics

1 answer:

Over [174]3 years ago

8 0

Answer:

x = 11

Step-by-step explanation:

Based on the two secants intersecting theorem, thus, we have:

(x + 5)*5 = (38 + 2)2

5x + 25 = (40)2

5x + 25 = 80

5x = 80 - 25 (subtraction property of equality)

5x = 55

Divide both sides by 5

x = 11

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What is the product of 84,90?

MAVERICK [17]

84•90 is 7,560.

ndheisn

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3 years ago

Use pi=3.14 to estimate the circumference of the circle to the nearest hundreth the diameter is 11 cm

TiliK225 [7]

The formula of circumference: 兀×diameter

In this case:

3.14×11
=34.54cm

Nearest hundreth = 2 demical places

Therefore, the answer is 34.54cm.

Hope it helps!

3 0

3 years ago

help me with the Quadratic equation.... x2+ (p - 5) x + 2q = 0 has the roots −3 and 6. Find the value of P and the value of q.

nirvana33 [79]

Step-by-step explanation:

The quadratic equation is x² + (p - 5)x + 2q = 0.

By Vieta's Formula,

we have SOR = -b/a and POR = c/a.

=> (-3) + (6) = -(p - 5) and (-3)(6) = 2q.

=> 3 = 5 - p and -18 = 2q

Hence, p = 2 and q = -9.

Alternate Method:

We have (x + 3) and (x - 6) as factors of the quadratic equation x² + (p - 5)x + 2q = 0.

=> (x + 3)(x - 6) = x² - 3x - 18.

By Comparing Coefficients,

(p - 5) = -3 and 2q = 18.

Hence p = 2 and q = -9.

8 0

2 years ago

Can someone please help

laila [671]

B hope i helped (:::

6 0

2 years ago

A teacher teaches two classes with 8 students each. Each student has a 95% chance of passing their class independent of the othe

dsp73

Answer:

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they pass, or they do not. The probability of an student passing is independent of other students, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability that all students pass in a class:

Class of 8 students, which means that $n = 8$

Each student has a 95% chance of passing their class independent of the other students, which means that $p = 0.95$

This probability is P(X = 8). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{8,8}.(0.95)^{8}.(0.05)^{0} = 0.6634$

Find the probability that, in exactly one of the two classes, all 8 students pass.

Two classes means that $n = 2$

0.6634 probability all students pass in a class, which means that $p = 0.6634$ .

This probability is P(X = 1). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,1}.(0.6634)^{1}.(0.3366)^{1} = 0.4466$

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

3 0

3 years ago