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3 years ago

Solve the inequality. |3m – 2| ≥ 1 m ≤ –1 or m ≥ 1

Mathematics

1 answer:

JulijaS [17]3 years ago

4 0

Answer:

m《⅓ or m ≥ 1

Step-by-step explanation:

|3m – 2| ≥ 1

3m - 2 ≥ 1

3m ≥ 3

m ≥ 1

-(3m - 2) ≥ 1

-3m + 2 ≥ 1

3m《1

m《⅓

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If you are going 200 miles per hour how much are you going per minute

Lapatulllka [165]

1 hour has 60 minutes.

Divide miles per hour by 60 to get miles per minute:

200 / 60 = 3.33 ( 3 1/3 ) miles per minute.

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3 years ago

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MATHS MIDDLE SCHOOL ANSWER ASAP PLEASE

Sveta_85 [38]

Answer:

A. 1

B. -1

C. 5

Step-by-step explanation:

A. Using the Formula, we get u sub 2 = 9-9+1, which is just 1

B. Using the Formula, we get u sub 3 = 1-3+1, which is equal to -1

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3 years ago

One hour after yolanda started walking from x to y, a distance of 45 miles, bob started walking along the same road from y to x.

Rufina [12.5K]

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3 years ago

The SAT scores have an average of 1200 with a standard deviation of 60. A sample of 36 scores is selected. a) What is the probab

LiRa [457]

Answer:

a) 0.0082

b) 0.9987

c) 0.9192

d) 0.5000

e) 1

Step-by-step explanation:

The question is concerned with the mean of a sample.

From the central limit theorem we have the formula:

$z=\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$

a) $z=\frac{1224-1200}{\frac{60}{\sqrt{36} } }=2.40$

The area to the left of z=2.40 is 0.9918

The area to the right of z=2.40 is 1-0.9918=0.0082

$\therefore P(\bar X\:>\:1224)=0.0082$

b) $z=\frac{1230-1200}{\frac{60}{\sqrt{36} } }=3.00$

The area to the left of z=3.00 is 0.9987

$\therefore P(\bar X\:$

c) The z-value of 1200 is 0

The area to the left of 0 is 0.5

$z=\frac{1214-1200}{\frac{60}{\sqrt{36} } }=1.40$

The area to the left of z=1.40 is 0.9192

The probability that the sample mean is between 1200 and 1214 is

$P(1200\:$

d) From c) the probability that the sample mean will be greater than 1200 is 1-0.5000=0.5000

e) $z=\frac{73.46-1200}{\frac{60}{\sqrt{36} } }=-112.65$

The area to the left of z=-112.65 is 0.

The area to the right of z=-112.65 is 1-0=1

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3 years ago

Help with Pre Calculus

marshall27 [118]

Answer:

The first option

Step-by-step explanation:

The domain of a rational function should be all real numbers except for when the denominator is equal to 0. To find when the denominator is equal to 0 you simply need to find the zeroes of the denominator... but in this case you can do that through factoring and using the quadratic equation.

So first step is going to be to factor out the GCF, which in this case is x. This gives you the equation. $x(2x^2-x-15)$ . So one of the zeroes is when x=0. Now to find the other two zeroes you can use the quadratic equation which is $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\$ . So to find the other zeroes you simply plug the values in. a=2, b=-1, c=-15

$x=\frac{-(-1)\pm\sqrt{(-1)^2-4(2)(-15)}}{2(2)}\\\\x=\frac{1\pm\sqrt{1-4(2)(-15)}}{4}\\\\x=\frac{1\pm\sqrt{121)}}{4}\\\\x=\frac{1\pm11}{4}\\\\x=\frac{12}{4}\\x=3\\\\x=\frac{-10}{4}\\x=-\frac{5}{2}$

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2 years ago