Surface area of a sphere = 4πr²
Surface area of the sphere = 4π(0.8)² = 8.0 ft²
Volume of a sphere = 4/3 πr³
Volume of the sphere = 4/3 π(0.8)³ = 2.1 ft³
Answer: Surface area = 8.0 ft² and volume - 2.1 ft³ (Answer C)
Answer:
21, 24, 29
Step-by-step explanation:
Replace n with 1, 2, and 3, and do the arithmetic.
first term = 1² +20 = 21
second term = 2² +20 = 24
third term = 3² +20 = 29
The first three terms are 21, 24, 29.
2cos²x + cosx − 1 = 0
(cosx+1)(2cosx-1)=0
so cosx+1=0
or 2cosx-1=0
1) cosx+1=0
cosx=-1
x=π+2πk, k∈Z
2) 2cosx-1=0
2cosx=1
cosx=0.5
x=+-
, k∈Z
find value for the interval [0, 2 pi )
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Answer:
(x-7)² = 36
The square root of both is √(x-7)² =√6²
x-7 = + or - 6
x-7 = 6 , then x = 13
x-7 = -6, then x = 1
So the values of x are 13 or 1