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Lady bird [3.3K]
3 years ago
5

What is Zirconium-78 protons and neutrons?​

Chemistry
1 answer:
11Alexandr11 [23.1K]3 years ago
4 0

Answer:

Zirconium has 40 protons and 51 neutrons

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Which is more likely in a settled and sedentary community?
Andre45 [30]

Answer:

Mar 29, 2015 · Their settlements are much more permanent and include houses, storage buildings, etc. They also need preservation methods and storage techniques, unlike the nomads. Sedentary Societies were first to be seen near waterways such as rivers.

Explanation:

4 0
4 years ago
The attraction between two oppositely charged atoms or group of atoms is which type of bond
Ber [7]

Answer:

ionic bond

An ionic bond is a type of chemical bond formed through an electrostatic attraction between two oppositely charged ions. Ionic bonds are formed between a cation, which is usually a metal, and an anion, which is usually a nonmetal. A covalent bond involves a pair of electrons being shared between atoms.

8 0
3 years ago
An organic compound, X, will react with calcium metal to produce a salt with the empirical formula CaC4H4O4. What could be the i
eduard
Answer is 2
bitanedioic acid has 4 carbon atoms
8 0
4 years ago
I need answers to question 1,2,3
sashaice [31]

Answer:

1. 0.125 mole

2. 42.5 g

3. 0.61 mole

Explanation:

1. Determination of the number of mole of NaOH.

Mass of NaOH = 5 g

Molar mass of NaOH = 23 + 16 + 1

= 40 g/mol

Mole of NaOH =?

Mole = mass /molar mass

Mole of NaOH = 5/40

Mole NaOH = 0.125 mole

2. Determination of the mass of NH₃.

Mole of NH₃ = 2.5 moles

Molar mass of NH₃ = 14 + (3×1)

= 14 + 3

= 17 g/mol

Mass of NH₃ =?

Mass = mole × molar mass

Mass of NH₃ = 2.5 × 17

Mass of NH₃ = 42.5 g

3. Determination of the number of mole of Ca(NO₃)₂.

Mass of Ca(NO₃)₂ = 100 g

Molar mass of Ca(NO₃)₂ = 40 + 2[14 + (3×16)]

= 40 + 2[14 + 48]

= 40 + 2[62]

= 40 + 124

= 164 g/mol

Mole of Ca(NO₃)₂ =?

Mole = mass /molar mass

Mole of Ca(NO₃)₂ = 100 / 164

Mole of Ca(NO₃)₂ = 0.61 mole

6 0
3 years ago
Propose a structure for an aromatic hydrocarbon, C9H12, that can form two C9H11Cl products on substitution of a hydrogen on the
Crank

Answer:

Explanation:

From the given study,

the molecular formula of the given aromatic compound = C9H12

the first process we suppose to carry out is to calculate the double bond equivalence.

So, the double bond equivalence DBE = {N_C+1-(\dfrac{(N_H+N_{Cl})-N_H}{2})  }

DBE = {9+1-(\dfrac{(12+0)-0}{2})  }

DBE = 4

Hence, the aromatic compound possesses 4 double bonds, this signifies that the might be a presence of benzene ring.

The substitutional products of the aromatic hydrocarbon C9H12 can be seen in the attached file below.

3 0
3 years ago
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