Propose a structure for an aromatic hydrocarbon, C9H12, that can form two C9H11Cl products on substitution of a hydrogen on the
aromatic ring with chlorine. You do not have to consider stereochemistry. In cases where there is more than one answer, just give one. Ignore the ortho, para-directing effects of the alkyl groups in answering this question. Consider only the number of nonequivalent hydrogens on the aromatic ring.
1 answer:
Answer:
Explanation:
From the given study,
the molecular formula of the given aromatic compound = C9H12
the first process we suppose to carry out is to calculate the double bond equivalence.
So, the double bond equivalence
DBE = 4
Hence, the aromatic compound possesses 4 double bonds, this signifies that the might be a presence of benzene ring.
The substitutional products of the aromatic hydrocarbon C9H12 can be seen in the attached file below.
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Answer:
C = K - 273.15
Explanation:
A kelvin is the same size as a Celsius degree.
Absolute zero is 0 K and the freezing point of water is 273.15 K.
To get the freezing point of water to be 0 °C, we must subtract 273.15 from the Kelvin reading (see Figure).
C = K – 273.15
C = 273.15 – 273.15
C = 0 °C
To get absolute zero on the Celsius scale, we repeat the process.
C = 0 – 273.15
C = –273.15 °C
