3- 5/9= 2.45
3- 23/9= .45
2.45/.45= 5.44
5.44^3/2= 81
Answer:
for part a i think it is the second one sorry if i do get it wrong and i couldnt answer the last one sorry
Step-by-step explanation:
Answer:
As the calculated value of z does not lie in the critical region the null hypothesis is accepted that the GPA mean of the night students is the same as the GPA mean of the day students.
Step-by-step explanation:
Here n= 20
Sample mean GPA = x`= 2.84
Standard mean GPA = u= 2.55
Standard deviation = s= 0.45.
Level of Significance.= ∝ = 0.01
The hypothesis are formulated as
H0: u1=u2 i.e the GPA of night students is same as the mean GPA of day students
against the claim
Ha: u1≠u2
i.e the GPA of night students is different from the mea GPA of day students
For two tailed test the critical value is z ≥ z∝/2= ± 2.58
The test statistic
Z= x`-u/s/√n
z= 2.84-2.55/0.45/√20
z= 0.1441
As the calculated value of z does not lie in the critical region the null hypothesis is accepted that the GPA mean of the night students is the same as the GPA mean of the day students.
Answer:
4
Step-by-step explanation:
the formula for radius is
so. 500 divided by pi times 10. then square root your final answer. cool. let's get started.
3.14*10 is 31.4, you can do that without thinking.
500/31.4=15.92
15.92= 3.99, or just 4
the radius is four.
