Question

I do not know what to do for the second one could someone please help me

Answer 1

Given:

Number $\sqrt{96}$

To find:

The simplest radical form.

Solution:

Let us first factor 96 using factor tree.

The image of the factor tree is attached below.

96 = 2 × 2 × 3 × 2 × 2 × 2

    = 2² × 3 × 2 × 2²

96 = 2² × 6 × 2²

Taking square root on both sides.

$\sqrt{96}=\sqrt{2^2\times 6 \times 2^2}$

$\sqrt{96}=\sqrt{4\times 6 \times 4}$

$\sqrt{96}=\sqrt{4^2\times 6$

Square number and square root get canceled.

$\sqrt{96}=4\sqrt{ 6}$

The simplest radical form of $\sqrt{96}$ is $4\sqrt{6}$.