(3x)2 – 7y2, when x = 3 and y = 2

The significance level is $\alpha=0.01$ and since we are conducting a right tailed test we need to find a critical value who accumulate 0.01 of the area in the right of the normal standard distribution and we got:

$z_{\alpha/2}= 2.326$

So we reject the null hypothesis is $z>2.326$

Step-by-step explanation:

For this case we define the random variable X as the number of entry-level swimmers and we are interested about the true population mean for this variable . On specific we want to test this:

Null hypothesis: $\mu \leq 15$

Alternative hypothesis: $\mu > 15$

And the statistic is given by:

$z =\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

The significance level is $\alpha=0.01$ and since we are conducting a right tailed test we need to find a critical value who accumulate 0.01 of the area in the right of the normal standard distribution and we got:

$z_{\alpha/2}= 2.326$

So we reject the null hypothesis is $z>2.326$

7 0

3 years ago

what is the distance between the points (23,-33) and (4,9) if necessary round your answer to two decimal places

Rufina [12.5K]

The distance between the points (23,-33) and (4,9) rounded to two decimal places is 46.10.

<h3>What is the distance between the points (23,-33) and (4,9)?</h3>

The distance between two points on a graph can be determined using the equation;

D = √[ ( x₂ - x₁ )² + ( y₂ - y₁ )² ]

Given that;

x₁ = 23
x₂ = 4
y₁ = -33
y₂ = 9

We substitute our values into the equation above.

D = √[ ( x₂ - x₁ )² + ( y₂ - y₁ )² ]

D = √[ ( 4 - 23 )² + ( 9 - (-33) )² ]

D = √[ ( -19 )² + ( 42 )² ]

D = √[ 361 + 1764 ]

D = √[ 2125 ]

D = 46.10

Therefore, the distance between the points (23,-33) and (4,9) rounded to two decimal places is 46.10.

Learn more about distance formula here: brainly.com/question/7592016

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7 0

2 years ago