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Orlov [11]
3 years ago
11

Hurry, it’s a test!!! Plz!

Mathematics
1 answer:
kondor19780726 [428]3 years ago
6 0

Answer:

estimate 215 answer 10

Step-by-step explanation:

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If f(1)=2f(1)=2 and f(n)=f(n-1)^2-n
katrin [286]

Answer:

f(4)=-3

Step-by-step explanation:

f(1)=2

f(n)=f(n-1)^2-n

If n=2

f(2)=f(2-1)^2-2

f(2)=f(1)^2-2

f(2)=2^2-2

f(2)=4-2

f(2)=2

If n=3

f(3)=f(3-1)^2 - 3

f(3)=f(2)^2 - 3

f(3)=2^2-3

f(3)=4-3

f(3)=1

if n=4

f(4)=f(4-1)^2 - 4

f(4)=f(3)^2 - 4

f(4)=1^2 - 4

f(4)=1-4

f(4)=-3

6 0
3 years ago
What is the value of z for the parallelogram shown? <br><br> A.130 <br> B.40<br> C.10<br> D.26
galben [10]
Z=10 because the opposite side is 50 degrees so the 5z=50

If you solve, z=10
7 0
3 years ago
Read 2 more answers
what is the first term of a geometric sequence in which the second term is 6 and the fourth term is 54
IRISSAK [1]
For a geometric sequence:
U_{n} = a * r^{n - 1}
U_{n} = the nth term, i.e. U₂ is the second term, U₃ is the third term, etc.
a = first term (U₁)
r = multiplier
n = number corresponding to the postion of the nth term in the sequence, e.g. for U₂, n = 2, for U₃, n = 3

According to the information:
U₂ = 6
U₄ = 54
So:
U_{2} = a * r^{(2) - 1} = 6 \\\\ a * r^{1} = 6 \\\\ ar = 6 \\
U_{4} = a * r^{(4) - 1} = 54 \\\\ a * r^{3} = 54 \\\\ ar^{3} = 54
Now, we have two equations in terms of a and r;
We can work out a by first working out r;
If we let the U₂ eq'n be [1] and the U₄ eq'n be [2];
Then, we do [2] ÷ [1] to cancel out the a and get an equation with only r that we are able to solve and then just solve it, like so:
\frac{ar^{3}}{ar} =  \frac{54}{6} \\\\ r^{2} = 9 \\\\ r = 3
Note: r has to be 3, and not -3, as the two given terms of the sequence tell us that the terms of the sequence will get bigger from each term to the next so r has to be above 1.

Now that we know r, we can sub it back into either [1] or [2] and solve for a, Its quicker and easier to sub it into [1] as we have no powers greater than 1 and we have smaller numbers to deal with (but you would get the same value of a either way), so:
U₂ = ar = 6
a(3) = 6
a = 6/3
a = 2
5 0
3 years ago
What is 1/10of 300 in a math equation
zhenek [66]
1/10 = 10/100
So we need to find 10% of 300.

0.10 x 300 = 30
5 0
3 years ago
Read 2 more answers
It took the high school hockey team 5h to travel to a tournament in Thunder Bay. They travelled by bus and plane a total distanc
mote1985 [20]
Entire distance = 1,320
Entire time = 5 hours

bus avg = 40 km/h
plane avg = 600 km/h

Working this by trial and error
1 hour bus 4 hour plane = 40 + 2,400 = 2,800 distance (too high)
2 hour bus 3 hour plane = 80 + 1,800 = 1,880 distance (too high)
3 hour bus 2 hour plane = 120 + 1,200 = 1,320 distance (Correct!!)

So, they traveled 3 hours by bus and 2 hours by plane
(yes, you had the right answer).

8 0
3 years ago
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