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3 years ago

According to the graph what is the value of the constant in the equation below

Mathematics

2 answers:

kogti [31]3 years ago

8 0

A is the answer to the problem

emmainna [20.7K]3 years ago

5 0

#A is the highest if you look at it, it says height=Constant x Width so that is your answer

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What are the domain and range of the exponential function below? <img src="https://tex.z-dn.net/?f=F%28x%29%20%3D%205%5

faust18 [17]

Answer:

Step-by-step explanation:

The domain is the set of x values for which the function is defined.

The range is the set of y values for which the function is defined.

Attached is the graph of the exponential function.

It is the basic graph of exponential function of y = 5^x which is shifted 6 units above (because of +6 at the end).

Looking at the graph, the domain is the set of all x values.

The range is anything above 6.

Correct answer is B.

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3 years ago

What is 190% of 66? Round to the nearest hundredth.

Aneli [31]

Answer:

190% of 66= 125.4

rounded to the nearest tenth:130

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3 years ago

Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.

o-na [289]

Answer: $\text{Length of AG=}\frac{2\sqrt{63}}{3}$

Explanation:

Please follow the diagram in attachment.

As we know median from vertex C to hypotenuse is CM

$\therefore CM=\frac{1}{2}AB$

We are given length of CG=4

Median divide by centroid 2:1

CG:GM=2:1

Where, CG=4

$\therefore GM=2$ ft

Length of CM=4+2= 6 ft

$\therefore CM=\frac{1}{2}AB\Rightarrow AB=12$

In $\triangle ABC, \angle C=90^0$

Using trigonometry ratio identities

$AC=AB\sin 30^0\Rightarrow AC=6$ ft

$BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3}$ ft

$CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3}$ ft

In $\triangle CAN, \angle C=90^0$

Using pythagoreous theorem

$AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}$

Length of AG=2/3 AN

$\text{Length of AG=}\frac{2\sqrt{63}}{3}$ ft

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3 years ago

Kailee has 4/5 finished of her math

Helen [10]

Answer:

1/5

Step-by-step explanation:

5/5 - 4/5 = 1/5

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3 years ago

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Veseljchak [2.6K]

The average is 105.5

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3 years ago

According to the graph what is the value of the constant in the equation below ​

According to the graph what is the value of the constant in the equation below