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3 years ago

Two parallel plates of area 0.155 m2 are separated by 0.00100 m. What is their capacitance?

Mathematics

1 answer:

ira [324]3 years ago

5 0

Answer:

1.37 x 10^-9 F

Step-by-step explanation:

(8.85 x 10^-12) * (0.155) = 1.37 E -12

1.37 E -12 / 0.00100 = 1.37 x 10^-9

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A water tank has the shape of an inverted right circular cone with base radius 3 meters and height 6 meters. Water is being pump

Ivan

Answer:

the rate of change is 3.8m/s

Step-by-step explanation:

The volume of the right circular cone is

$V= \frac{\pi*r^2h}{3}.$

The rate of change of volume is

$\frac{dV}{dt} =\frac{d}{dt}( \frac{\pi*r^2h}{3})=\frac{\pi}{3} \frac{d}{dt}(r^2h)=\frac{\pi}{3}(2rh\frac{dr}{dt}+r^2\frac{dh}{dt})$

In order to proceed further we have to define r in terms of h so tht we can compute the derivative above.

The ratio between h and r is

$\frac{h}{r}=\frac{6}{3} =2$

Therefore $r=\frac{h}{2}$ .

We plug that into the derivative above and get:

$2rh\frac{dr}{dt}+r^2\frac{dh}{dt}=\frac{h^2}{2}\frac{dh}{dt}+\frac{h^2}{4}\frac{dh}{dt}=\frac{3h^2}{4}\frac{dh}{dt}.$

Thus

$\frac{dV}{dt}=\frac{\pi}{3}\frac{3h^2}{4}\frac{dh}{dt}$

Now for the numerical part.

The rate of change of volume $\frac{dV}{dt}$ is $12\frac{m^3}{s}$ , so when the water is 2 meters deep $h=2$ , therefore:

$12=\frac{\pi*3*2^2}{4*3} \frac{dh}{dt} \\\\\therefore \boxed{ \frac{dh}{dt}=3.8m/s.}$

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=3%20%5Csqrt%7B375%7D%20" id="TexFormula1" title="3 \sqrt{375} " alt="3 \sqrt{375} " align="abs

Darina [25.2K]

Its 15v15 this was pretty easy

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3 years ago

V+5+9v-9 what’s the answer

Luda [366]

Answer:

-4+10v

Step-by-step explanation:

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3 years ago

Read 2 more answers

Find the product of -43, 7, and -21

aivan3 [116]

(-43) x 7 x (-21) = 6,321

6 0

3 years ago

Read 2 more answers

Please help need quickly!

MAXImum [283]

Pythagoras
28^2-19^2= 423
Square root of 423 = 20.5669638

Answer = 20.5669638

4 0

3 years ago