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xz_007 [3.2K]
2 years ago
12

Speedy Cab Company uses the following to determine fares:

Mathematics
1 answer:
yarga [219]2 years ago
6 0
0.75x + 5.00 = t yep
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The Clark family and the Lee family each used their sprinklers last summer. The water output rate for the Clark family's sprinkl
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A circular pool if filling with water. Assuming the water level will be 4' deep and the diameter is 20' , what is the volume of
Yuliya22 [10]

35,569.92 L of water is required to fill the pool

Step-by-step explanation:

  • Step 1: Find the area of the circular pool when radius = 20/2 = 10 ft

⇒ Area = πr² = 3.14 × 10² = 314 ft²

  • Step 2: Find the volume of the pool

Volume = Area × Depth

             = 314 × 4 = 1256 ft³

  • Step 3: Convert the volume into liters.

Volume of water = 1256 × 28.32 = 35,569.92 L (∵1 ft³ = 28.32 L)

8 0
3 years ago
Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c
GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(c) The value of P (X < 30) is 0.9502.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0

The value of E (X) is 10.

The parameter λ is:

\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10

(a)

Compute the value of P (X > 10) as follows:

P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353

Thus, the value of P (X > 20) is 0.1353.

(c)

Compute the value of P (X < 30) as follows:

P(X

Thus, the value of P (X < 30) is 0.9502.

(d)

It is given that, P (X < x) = 0.95.

Compute the value of <em>x</em> as follows:

P(X

Take natural log on both sides.

ln(e^{-0.10x})=ln(0.05)\\-0.10x=-2.996\\x=\frac{2.996}{0.10}\\ =29.96\\\approx30

Thus, the value of x is 30.

7 0
3 years ago
Add:
True [87]

Answer:

1. -195

2.-771

3. 2

1. 9

2.-3

3. -10

4. 205

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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