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2 years ago

I need help please i’ll give u a brainliest

Mathematics

1 answer:

kicyunya [14]2 years ago

3 0

Answer:

3 of them. Hope this helps!

Step-by-step explanation:

You might be interested in

Which of the following sets include all rational numbers?

kicyunya [14]

It's the Second one and the third one

Step-by-step explanation:

Pie is irrational so you can easily cross it off and it leads to to the second one and the third one

4 0

3 years ago

A box at the post office has dimensions as shown below. A rectangular prism with a length of 12 inches, width of 8 inches, and h

steposvetlana [31]

Answer: 1536 inches

Step-by-step explanation:

Fron the question, a rectangular prism has a length of 12 inches, width of 8 inches, and then a height of 16 inches. The volume can be gotten by multiplying the length by the width and height.

Volume= length × width × height

Volume = 12 × 8 × 16

Volume = 1536 inches

The volume of the box is 1536 inches.

5 0

3 years ago

A gambler has a coin which is either fair (equal probability heads or tails) or is biased with a probability of heads equal to 0

yawa3891 [41]

Answer:

(a) 0.1719

(b) 0.3504

Step-by-step explanation:

For every coin the number of heads follows a Binomial distribution and the probability that x of the 10 times are heads is equal to:

$P(x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{10-x}$

Where n is 10 and p is the probability to get head. it means that p is equal to 0.5 for the fair coin and 0.3 for the biased coin

So, for the fair coin, the probability that the number of heads is less than 4 is:

$P(x$

Where, for example, P(0) and P(1) are calculated as:

$P(0)=\frac{10!}{0!(10-0)!}*0.5^0*(1-0.5)^{10-0}=0.0009\\P(1)=\frac{10!}{1!(10-1)!}*0.5^1*(1-0.5)^{10-1}=0.0098$

Then, $P(x$ , so there is a probability of 0.1719 that you conclude that the coin is biased given that the coin is fair.

At the same way, for the biased coin, the probability that the number of heads is at least 4 is:

$P(x\geq4 )=P(4)+P(5)+P(6)+...+P(10)$

Where, for example, P(4) is calculated as:

$P(4)=\frac{10!}{4!(10-4)!}*0.3^4*(1-0.3)^{10-4}=0.2001$

Then, $P(x\geq4 )=0.3504$ , so there is a probability of 0.3504 that you conclude that the coin is fair given that the coin is biased.

7 0

3 years ago

Its the last one:) please help. giving brainlist

diamong [38]

Answer:

$5$

Step-by-step explanation:

Segments are named by their endpoints. Therefore, segment PQ will have endpoints P and Q. The length of the segment is equal to the distance between these points.

To find the distance between P and Q given their coordinates, use the distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$