To factor a quadratic of the form ax^2+bx+c you need to find two values, j and k, that satisfy two conditions:
ac=jk and b=j+k in this case:
ac=jk=-18 and b=j+k=7 so j and k must be 9 and -2
Now replace bx with jx and kx in the original equation...
x^2-2x+9x-18 and factor the 1st and 2nd pair of terms...
x(x-2)+9(x-2) which is equal to
(x+9)(x-2)
Answer:
<RQP = 70°
Step-by-step explanation:
<RQP = 1/2 (140)
<RQP = 70°
I got E and F. A would be correct as is I think, B is 9^2x, C, correct as is, D, is 9 ^2x, and E and F is 9^x
