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7nadin3 [17]
3 years ago
12

How many moles of Al are necessary to form 28.2 g of AlBr₃ from this reaction:

Chemistry
1 answer:
shtirl [24]3 years ago
5 0
<h3>2AL° + 3Br2° 2AL Br3</h3><h3>this is an oxidation - reduction (redox) reaction </h3><h3>6Br° + 6e 6Br ( reduction )</h3><h3>2AL° - 6e 2AL. ( oxidation )</h3><h3>Br2 is an oxidizing agent AL is a2 reducing agent</h3>
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