Answer:
A function that has an axis of symmetry at x = 3 is:
f (x) = x ^ 2 - 6x - 1
Step-by-step explanation:
A parabola has an axis of symmetry at x = 3 if the x-value of the vertex is 3.
f(x) = x^2 + 3x + 1 = x^2 + 3x + 9/4 - 5/4 = (x + 3/2)^2 - 5/4 => vertex = (-3/2, -5/4)
f(x) = x^2 - 3x - 3 = x^2 - 3x + 9/4 - 21/4 = (x - 3/2)^2 - 21/4 => vertex = (3/2, -21/4)
f(x) = x^2 + 6x + 3 = x^2 + 6x + 9 - 6 = (x + 3)^2 - 6 => vertex = (-3, -6)
f(x) = x^2 - 6x - 1 = x^2 - 6x + 9 - 10 = (x - 3)^2 - 10 => vertex = (3, -10)
Therefore, f(x) = x^2 - 6x - 1 has an axis of symmetry at x = 3.
Hope This HELPS!!!
We know that
<span>The cosine of the sum of two angles </span><span>is defined by the following trigonometric identity
</span>cos(A + B) = cos A cos B − sin A sin <span>B
A=60</span>°
B=105°
cos A=cos 60
cos B=cos 105
sin A=sin 60
sin B=sin 105
then
cos(60 + 105) = cos 60 cos 105 − sin 60 sin 105
cos(165) = cos 60 cos 105 − sin 60 sin 105
the answer is
cos (105°)
Answer:
I believe they are correct. Sorry this is late
Step-by-step explanation:
Answer:
The answer is -x+26.
Step-by-step explanation:
First you distribute the -3 into the parthensis and you get -3x+15. You write the whole expression again plus the -3x+15 you got from the distributing part so 8-3x+15+2x+3. You combine the like terms so the x with the x and the numbers with the numbers. From there you get the answer of -x+26. I hope this helps you! If you need more clarification or more help please type it in the comments below. Thanks!
