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photoshop1234 [79]
3 years ago
10

In circle K, what is the value of x? x = 30° x = 25° x = 20° x = 15º A triangle inscribed in a circle having one side as diamete

r, center labeled as K and two angles labeled X degrees and seventy-five degrees. The angle with x degrees is on the right side of the diameter. The 75 degree angle is on the left side of the diameter.

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
8 0

Answer:

x = 15°

Step-by-step explanation:

<em><u>The segment is a diameter, So let us assume the part in which there lies the triangle as a semicircle.</u></em>

=> <em>A triangle inscribed in a semi-circle will always have one of its angle equal to 90</em>

=> <em>So the angle (not 75 and x) is 90 degrees.</em>

<em>=> To find the value of x, we'll subtract rest of the angles from 180 degrees (because the interior angles of a triangle add up to 180°)</em>

<em>So,</em>

=> x = 180-90-75

=> x = 15°

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I need some help, please
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4 0
3 years ago
× + 20 + 2× = 10 - 2× - 15
OlgaM077 [116]

Answer:

The answer is -5

Step-by-step explanation:

\mathrm{Group\:like\:terms}\\x+2x+20=10-2x-15

\mathrm{Add\:similar\:elements:}\:x+2x=3x\\3x+20=10-2x-15

\mathrm{Group\:like\:terms}\\3x+20=-2x+10-15

\mathrm{Add/Subtract\:the\:numbers:}\:10-15=-5\\3x+20=-2x-5

\mathrm{Subtract\:}20\mathrm{\:from\:both\:sides}\\3x+20-20=-2x-5-20

\mathrm{Simplify}\\3x=-2x-25

\mathrm{Add\:}2x\mathrm{\:to\:both\:sides}\\3x+2x=-2x-25+2x

\mathrm{Simplify}\\5x=-25

\mathrm{Divide\:both\:sides\:by\:}5\\\frac{5x}{5}=\frac{-25}{5}

\mathrm{Simplify}\\x=-5

Hope this helps you greatly!

Have a great afternoon!

6 0
3 years ago
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