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Feliz [49]
3 years ago
8

Help me out with this question (geometry/angle bisectors)

Mathematics
1 answer:
dimulka [17.4K]3 years ago
4 0
You have to add both of the equations for a 180° percent
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Find x, if 3x − 5(y + x ) ^2 = 16 and 4x + 2(y + x )^ 2 = 30
lana66690 [7]

Answer:

x = 7

Step-by-step explanation:

Start by solving for (y+x)^2 which is a common expression for both equations. Then in the first equation:

3\,x5\,(y+x)^2=16\\3x-16=5\,(y+x)^2\\(y+x)^2=\frac{3\,x-16}{5}

and in the second equation:

4\,x+2\,(y+x)^2=30\\2\,(y+x)^2=30-4\,x\\(y+x)^2=15-2\,x

Now we make the two (y+x)^2 expressions equal so we get:

\frac{3\,x-16}{5} =15-2\,x\\3\,x-16=75-10\,x\\13\,x=75+16\\13\,x=91\\x=7

8 0
3 years ago
What is a corner of a kitchen counter?
IRINA_888 [86]

Answer:

vertices

Step-by-step explanation:

The corner of a shape or object is the vertices

8 0
2 years ago
Product of a number and 6​
Marat540 [252]

Hey there!

Your answer is 6n.

"Product of" represents multiplication. So, we can do a number times 6, or "6n".

Have a terrificly amazing day! :D

4 0
3 years ago
On the first day a total of 40 items were sold for $356. Define the variables and write a system of equations to find the number
Alina [70]
<h3><u><em>Question:</em></u></h3>

On the first day, a total of 40 items were sold for $356. Pies cost $10 and cakes cost $8. Define the variables, write a system of equations to find the number of cakes and pies sold, and state how many pies were sold.

<h3><em><u>Answer:</u></em></h3>

The variables are defined as:

"c" represent the number of cakes sold and "p" represent the number of pies sold

The system of equations used are:

c + p = 40 and 8c + 10p = 356

18 pies and 22 cakes were sold

<h3><em><u>Solution:</u></em></h3>

Let "c" represent the number of cakes sold

Let "p" represent the number of pies sold

Cost of 1 pie = $ 10

Cost of 1 cake = $ 8

Given that total of 40 items were sold

number of cakes + number of pies = 40

c + p = 40 ------ eqn 1

<u><em>Given items were sold for $356</em></u>

number of cakes sold x Cost of 1 cake + number of pies sold x Cost of 1 cake = 356

c \times 8 + p \times 10 = 356

8c + 10p = 356  ----- eqn 2

<u><em>Let us solve eqn 1 and eqn 2</em></u>

From eqn 1,

p = 40 - c    ---- eqn 3

Substitute eqn 3 in eqn 2

8c + 10(40 - c) = 356

8c + 400 - 10c = 356

-2c = - 44

c = 22

<em>Substitute c = 22 in eqn 3</em>

p = 40 - c

p = 40 - 22

p = 18

Thus 18 pies and 22 cakes were sold

3 0
3 years ago
If pears cost $1.95 per pound,how much would 2 pounds cost?
Reika [66]

Answer:

$3.90

Step-by-step explanation:

1.95(2)

= $3.90

8 0
3 years ago
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