Help me out with this question (geometry/angle bisectors)
1 answer:
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<u>Answer: </u>
The point slope form of the line that passes through (-8,2) and is parallel to a line with a slope of -8 is 8x + y + 62 = 0
<u>Solution: </u>
The point slope form of the line that passes through the points and parallel to the line with slope “m” is given as
--- eqn 1
Where “m” is the slope of the line.
are the points that passes through the line.
From question, given that slope “m” = -8
Given that the line passes through the points (-8,2).Hence we get
By substituting the values in eqn 1, we get the point slope form of the line which is parallel to the line having slope -8 can be found out.
y-2=-8(x-(-8))
On simplifying we get
y – 2 = -8(x +8)
y – 2 = -8x -64
y – 2 +8x +64 = 0
8x + y +62 = 0
Hence the point slope form of given line is 8x + y +62 = 0
Answer:
n=35; q=33 coins.
Step-by-step explanation:
1) if number of nickles is 'n' and the quaters is 'q' then it is possible to write:
n+q=68 - 'she counted 68 coins...' - the 1st equation of system;
0.25q+0.05n=10 - '10$ in it' - the 2d equation of the system.
2) it is possible to make up and solve the next system of two equations: