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astraxan [27]
3 years ago
5

What is the (y) to this equation -5x+2y=13 5x+y=-1

Mathematics
1 answer:
irakobra [83]3 years ago
4 0

Step-by-step explanation:

I hope this helps you good luck

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The table shows values for functions f(x) and g(x) .
Bas_tet [7]

Answer:

There is no correct answer

Step-by-step explanation:

4x+20

2x+6

4x+20=2x+6

4x–2x=6–20

2x=–14

x=–7

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4 years ago
Which one has the exact same amount of coins as the one above?
dezoksy [38]

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its b

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Two lengths are in ratio 7:8.if the first length is 273. What amount is the second length
Sergio [31]

Answer:

312

Step-by-step explanation:

Since the ratio is 7:8, mark it as 7x:8x.

Now, they said that the first length is 273. Solve the equation:

7x=273

x=39

Substitute it into 8x. 39*8=312. That's your answer.

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3 years ago
Ill mark brainilist or whatever, just answer please fast. Need this done asap
Archy [21]

Answer:

true

Step-by-step explanation:

6 0
3 years ago
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A contractor is required by a county planning department to submit one, two, three, four, five, or six forms (depending on the n
Ratling [72]

Answer:

a)

k = \dfrac{1}{21}

b) 0.476

c) 0.667    

Step-by-step explanation:

We are given the following in the question:

Y = the number of forms required of the next applicant.

Y: 1, 2, 3, 4, 5, 6

The probability is given by:

P(y) = ky

a) Property of discrete probability distribution:

\displaystyle\sum P(y_i) = 1\\\\\Rightarrow k(1+2+3+4+5+6) = 1\\\\\Rightarrow k(21) = 1\\\\\Rightarrow k = \dfrac{1}{21}

b) at most four forms are required

P(y \leq 4) = \displaystyle\sum^{y=4}_{y=1}P(y_i)\\\\P(y \leq 4) = \dfrac{1}{21}(1+2+3+4) = \dfrac{10}{21} = 0.476

c) probability that between two and five forms (inclusive) are required

P(2\leq y \leq 5) = \displaystyle\sum^{y=5}_{y=2}P(y_i)\\\\P(2\leq y \leq 5) = \dfrac{1}{21}(2+3+4+5) = \dfrac{14}{21} = 0.667

8 0
3 years ago
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