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Inessa05 [86]
3 years ago
12

Help. Image attached

Mathematics
1 answer:
Sophie [7]3 years ago
6 0

0.10

Hope I helped! :)

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If a triangle has side lengths of 5.6 yards, 7.1 yards, and x yards, find the range of possible values of x.
ANTONII [103]
Hi!

To find the range of possible values of x, we have to side 1 from side 2...

7.1 - 5.6 = 1.5

The smallest side x could be is 1.5.
Now add side 1 to side 2

7.1 + 5.6 = 12.7

The biggest side x could be is 12.7

So x could be anywhere from 1.5 to 12.7 (or, 1.5 < x < 12.7)

Hope this helps! :)
7 0
3 years ago
The slope and unit rate
Julli [10]
The slope is 4/5 I think
6 0
3 years ago
Solve the equation for x, and enter your answer below.<br>7 x -5= 65​
Sedaia [141]

x=10

Step-by-step explanation:

7x - 5=65

+5 +5 so the 5's cancel so add 5 to 65

7x =70 because you add 5 to 65 to get 70

7x 7

7 x cancels out so you answer will be

x=10

3 0
3 years ago
Read 2 more answers
Convert the rectangular coordinates (-9, 3V3) into polar form. Express the angle
Whitepunk [10]

Answer:

(6\sqrt{3},\,\frac{5\pi}{6})

Step-by-step explanation:

The radius  r  can be found from the relationship

 r^2=x^2+y^2\\r^2=(-9)^2+(3\sqrt{3})^2\\r^2=81+27=108\\r=\sqrt{108}\\r=6\sqrt{3}

The point is in Quadrant II (-, +), so use the inverse cosine function to find the angle.

\cos{\theta}=\frac{x}{r}=\frac{-9}{6\sqrt{3}}\\\cos{\theta}=-\frac{9}{6\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}}\\\cos{\theta}=-\frac{9\sqrt{3}}{6\cdot3}\\\cos{\theta}=-\frac{\sqrt{3}}{2}\\\\\cos^{-1}\frac{-\sqrt{3}}{2}}=\frac{5\pi}{6}

See the attached image.

7 0
3 years ago
PLEASE HELP THANK YOUUUUU
katrin [286]

Answer:

can you pop out all the boxes I need to see what the numbers are to get a further understanding

8 0
2 years ago
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