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3 years ago

Help me, the question is down below

Mathematics

2 answers:

ruslelena [56]3 years ago

3 0

Answer:

Step-by-step explanation:

6.3/3 = 2.1

12.6/6 = 2.1

18.9/9 = 2.1

Margaret [11]3 years ago

3 0

The answer is C.

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Find all the interior angle measures of triangle ABC, if m∠A = 3x + 10, m∠B = 5x − 1, and m∠C = x. answers: m∠A = 60°, m∠B = 94°

tester [92]

Answer:

Step-by-step explanation:

Total interior angles in a triangle=180 degrees

That is: 3x + 10 + 5x - 1 + x =180

9x+9=180

9x=180-9

9x=171

x=171/9

x=19

Therefore

Angle A =67 degrees

Angle B= 94 degrees

Angle C = 19 degrees

3 0

3 years ago

The expression i/pt represents the rate of instrest being charged if a loan of p dollars for t years required i dollars in intre

zysi [14]

Answer:

7.3%

Step-by-step explanation:

Given:

<em>Formula for Rate of interest </em> $R$ :

$R=\dfrac{i}{Pt}$

Where $i$ is the rate of interest.

$P$ dollars is the loan and

$t$ years is the time for which interest is to be paid

$P =\$690\\t=3\ years\\i=\$151.11$

To find:

$R=?$

Solution:

Putting the given values in the formula:

$R=\dfrac{151.11}{690 \times 3}\\\Rightarrow R=\dfrac{151.11}{2070}\\\Rightarrow R=0.073$

Multiply the above value with 100 to find the percentage.

i.e.

$R=0.073\times 100 = \bold{7.3\%}$

Therefore, the answer is <em>7.3%</em>

8 0

4 years ago

A student gets 9 out of 15 problems correct on a homework assignment.

Alex777 [14]

Answer:40%.

Since the student got 60% correct, the remaining percentage would be the part they got incorrect.

I got 60% by translating 9/15 into a decimal and moving the decimal point to create a percentage.

Hope this helps!

Step-by-step explanation:

7 0

4 years ago

Solve the following equation:

Rama09 [41]

Complete the square.

$z^4 + z^2 - i\sqrt 3 = \left(z^2 + \dfrac12\right)^2 - \dfrac14 - i\sqrt3 = 0$

$\left(z^2 + \dfrac12\right)^2 = \dfrac{1 + 4\sqrt3\,i}4$

Use de Moivre's theorem to compute the square roots of the right side.

$w = \dfrac{1 + 4\sqrt3\,i}4 = \dfrac74 \exp\left(i \tan^{-1}(4\sqrt3)\right)$

$\implies w^{1/2} = \pm \dfrac{\sqrt7}2 \exp\left(\dfrac i2 \tan^{-1}(4\sqrt3)\right) = \pm \dfrac{2+\sqrt3\,i}2$

Now, taking square roots on both sides, we have

$z^2 + \dfrac12 = \pm w^{1/2}$

$z^2 = \dfrac{1+\sqrt3\,i}2 \text{ or } z^2 = -\dfrac{3+\sqrt3\,i}2$

Use de Moivre's theorem again to take square roots on both sides.

$w_1 = \dfrac{1+\sqrt3\,i}2 = \exp\left(i\dfrac\pi3\right)$

$\implies z = {w_1}^{1/2} = \pm \exp\left(i\dfrac\pi6\right) = \boxed{\pm \dfrac{\sqrt3 + i}2}$

$w_2 = -\dfrac{3+\sqrt3\,i}2 = \sqrt3 \, \exp\left(-i \dfrac{5\pi}6\right)$

$\implies z = {w_2}^{1/2} = \boxed{\pm \sqrt[4]{3} \, \exp\left(-i\dfrac{5\pi}{12}\right)}$

3 0

2 years ago

If ur nice please answer me

Llana [10]

Hope this answer helps

5 0

3 years ago